Want this question answered?
201
326g
If all of the quantities stated actually reacted, the law of the conservation of mass shows that the mass of carbon dioxide produced would be 40 - 18 or 22 grams.
22 grams carbon dioxide (0.5 moles)
The mass of carbon dioxide is 141,2 g.
201
326g
mass of CaCO3 = 246 grams
The amount of carbon that one person produces in a day is estimated to be 900 grams. Humans produce carbon dioxide when they breathe out.
Moles of carbon dioxide = grams/amu of carbon dioxide. Moles = 19g/44amu Moles of carbon dioxide = .432
If all of the quantities stated actually reacted, the law of the conservation of mass shows that the mass of carbon dioxide produced would be 40 - 18 or 22 grams.
800 g oxygen are needed.
22 grams carbon dioxide (0.5 moles)
6 grams
The mass of carbon dioxide is 141,2 g.
The answer is 19,288 g cacium carbonate.
The equation given shows that each formula mass of calcium carbonate produces one formula mass of CO2. The gram formula masses of calcium carbonate and carbon dioxide are 100.09 and 44.01 respectively. Therefore, to produce 4.4 grams of carbon dioxide, 4.4(100.09/44.01), or 10 grams of calcium carbonate, to the justified number of significant digits, are needed.