The answer to this question is highly variable because it depends on the diet that the cow is on, her weight, her age, and even where she lives.
A cow farts.
You don't !! !! !!
102
This question can not be answered, not even by your teacher: not enough correct information." How many grams (of WHAT ?) would 29.48 L of chlorine gas produce (after doing WHAT ?) "
Yes. They can produce more or less, depending on their diet.
You would need 5.7 grams of mercury II oxide to produce 1.56 L of oxygen gas according to the following reaction at those conditions.
To produce 10 grams of table salt (sodium chloride), you would need roughly 10 grams of chlorine gas. This is because the balanced chemical equation for the reaction between sodium and chlorine to form sodium chloride (table salt) is 2Na + Cl2 -> 2NaCl.
45,0 grams of hydrogen gas have 135,5.10e23 atoms.
It is not measured in grams but PPM because it is a gas.
2 moles of sodium will produce 1 mole of hydrogen gas according to the chemical equation 2Na + 2H2O → 2NaOH + H2. The molar mass of sodium is 23 g/mol and of hydrogen gas is 2 g/mol. Thus, 2 moles of sodium is 46 grams (2 moles * 23 g/mol), which will produce 2 moles of hydrogen gas.
8 grams. Or more exactly, in 30.0 grams of methane there is 7.54 grams of hydrogen.
In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).