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You need 150,41 g oxygen.
5
319g Cl2 are needed.
Call the unknown mass x. The Law of Constant Proportions states that x/13 must equal 31/71, or x must be (13)(31)/71 or about 5.7 grams, to the justified number of significant digits.
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800 g oxygen are needed.
You need 150,41 g oxygen.
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
i think that you have to add 100 gramd to produce the amount of 900 grams
5
16.0 g
10.1 grams
16,45 g nitrogen are needed.
319g Cl2 are needed.
A lot
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.
Call the unknown mass x. The Law of Constant Proportions states that x/13 must equal 31/71, or x must be (13)(31)/71 or about 5.7 grams, to the justified number of significant digits.