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Nothing is produced, 500g potassium chlorate will be the same 500 g potassium chlorate after reaction. Actually there is no reaction at all.

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Q: How many grams of potassium chlorate would be produced by reacting 500 grams of potassium chlorate with oxygen gas?
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Related questions

What elements is potassium chlorate a compound of?

Potassium chlorate is KClO3 and it consists of potassium, chlorine and oxygen.


How many oxygen atoms are there in one molecule of potassium chlorate?

Potassium chlorate (KClO3) has 3 oxygen atoms.


What is the ionic compound for potassium chlorate?

potassium, chloride and oxygen


What element is both found in potassium chlorate and zinc nitrate?

Oxygen is present in both zinc nitrate and potassium chlorate. Potassium chlorate = KClO3 and zinc nitrate = ZnNO3 .


How many moles of potassium chlorate are needed to give 1.50 moles of oxygen?

The answer is 1 mole potassium chlorate.


How oxygen is prepared in lab using potassium chlorate?

Potassium Chlorate, when heated gives Potassium Chloride and Oxygen. You can use Manganese Dioxide as a catalyst to speed up the reaction.


Decomposition of potassium chlorate to potassium chloride?

Potassium chlorate contains potassium, chlorine, and oxygen. It is used in safety matches, explosives, as an oxidizing agent, to prepare oxygen, and as a disinfectant.


What is potassium chlorate used for?

it is used to prepare oxygen


How do you calculate the theoretical mass percentage of oxygen in potassium chlorate?

I believe it is: %O=mass of 3 mol of O / mass of 1 mol of potassium chlorate *100% If you measured it: %O=mass of oxygen lost / mass of potassium chlorate *100%


How much oxygen gas in grams can be prepared from 86.8 g of potassium chlorate?

Pure oxygen gas can be prepared in the laboratory by the decomposition of solid potassium chlorate to form solid potassium chloride and oxygen gas. 34.0 g


How many moles of potassium chlorate must be used to produce 6 moles if oxygen gas?

Four moles of potassium chlorate are needed.


How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?

2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3