A 2M NaCl solution contains approximately 58.5g of salt. So to make two liters of a 2M solutions you would need 117g of salt dissolved in 2 liters of water.
NaF has an atomic mass of 42, therefore if you dissolve 42 grams (1 mole) of it in 2 liters of water you get a molarity of 0.5 moles/Liter.
The mass of sodium chloride is 233,76 g.
Because you have 6.68 moles of Li2SO4 and 2.500 liters of water, the overall molarity of your solution is 2.67 M.
4.00 grams of NaOH have been added to 2.00 liters of water. The molarity of this solution is?
the answer is 23 grams
This is a homogeneous solution of ammonium hydroxide in water.
5g of sugar. 10 liters = 10,000ml, 500g / 10,000ml = 5g / 100ml.
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
233,771 g sodium chloride
Molarity (concentration ) = moles of solute/Liters of solution 250.0 ml = 0.250 liters 2.431 grams H2C2O4 * 2H2O ( 1mole cpd/ 126.068 grams) = 0.01928 moles H2C2O4 * 2H2O Molarity = 0.01928 moles cpd/0.250 liters = 0.07712 Molarity
This molarity is 0,618.
Whether all of the sugar dissolved or not, and it would be very unlikely that it would all dissolve in that small an amount of water, the total mass of the solution or mixture would be 250 grams.
The weight of the solution and thereby the weight of the solute.
Solute X is soluble in water
first determine the number ofmoles dissolved in given solution then .5 moles moles dissolved in 800g. as comparison with 1000g of water, we know 100g of water dissolve only.1 moles of a glucose so we .7moles of glucose dissolve in 800g.
Just add the two masses: 40 + 120 = 160 grams.
Water dissolved in water ??