3 x 2 x 23 = 138g
3.121x10-5 Grams of Na2CO3
234 grams :)
234 grams
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
The gram atomic mass of sodium is 22.9898, the formula of the least hydrated form of sodium phosphate is Na3PO4.10 H2O, and the gram formula unit mass of this sodium phosphate is 344.09. Therefore, the mass fraction of sodium in this sodium phosphate is 3(22.9898)/344.09 or about 0.20044, and the grams of sodium in 7.2 grams of this sodium phosphate is 1.44 grams of sodium, to the justified number of significant digits.
3 x 2 x 23 = 138g
6into23equals 138 6into23equals 138
3.121x10-5 Grams of Na2CO3
There are 69 grams of sodium in 3 moles of sodium carbonate (Na₂CO₃). This is because there are two moles of sodium atoms in one mole of sodium carbonate, and the molar mass of sodium is 22.99 g/mol.
My Shaft
1.06 g of Na2CO3 was added to 1 liter of water to prepare a 0.02 N (normality) solution because that specific mass of Na2CO3 provides the required molarity of Na+ ions in the solution. Normality is a measure of concentration that relates to the equivalents of a substance rather than the moles, and in the case of Na2CO3, it is important to account for the stoichiometry of the compound to achieve the desired concentration.
The molar mass of sodium carbonate (Na2CO3) can be calculated by adding the atomic masses of its constituent elements. The atomic masses of sodium (Na), carbon (C), and oxygen (O) are approximately 23 g/mol, 12 g/mol, and 16 g/mol, respectively. Therefore, the molar mass of sodium carbonate is approximately 105 g/mol when rounded to the nearest gram.
To prepare a 0.1 N solution of sodium carbonate in 1 liter, dissolve 5.3 grams of anhydrous sodium carbonate (Na2CO3) in distilled water and make up the volume to 1 liter with water. Stir well until the sodium carbonate is completely dissolved. This will give you a 0.1 N solution of sodium carbonate in 1 liter.
The molar mass of sodium carbonate is approximately 106 grams per mole.
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of Na2CO3 (sodium carbonate) is 105.99 g/mol. So, to find the grams in 0.577 mol of Na2CO3, you would calculate 0.577 mol * 105.99 g/mol = approximately 60.98 grams of Na2CO3.
234 grams :)
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------