To prepare a 0.01N solution of sodium metabisulfite, you would need 2.31 grams of sodium metabisulfite per liter of solution.
To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.
To determine the grams of sodium sulfate needed, you first need to specify the molarity (M) of the sodium sulfate solution. Once you have the molarity, you can use the formula: grams = molarity (M) x volume (L) x molar mass (g/mol). This will give you the amount of sodium sulfate in grams needed to make the solution.
To calculate the grams of sodium thiosulfate needed, first determine the molar mass of Na2S2O3 (158 g/mol). Step 1: Calculate the number of moles needed using the formula: moles = Molarity * Volume (in liters) moles = 0.025 * 2 (since 2000 ml is 2 liters) = 0.05 moles Step 2: Calculate the grams needed using the formula: grams = moles * molar mass grams = 0.05 * 158 = 7.9 grams Therefore, you would need 7.9 grams of sodium thiosulfate to make 2000 ml of a 0.025N solution.
The mass of the solution would be the sum of the mass of the sodium chloride and the mass of water. So, the mass of the solution would be 17.8 grams (NaCl) + 217 grams (water) = 234.8 grams.
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
To determine the grams of sodium sulfate needed, you first need to specify the molarity (M) of the sodium sulfate solution. Once you have the molarity, you can use the formula: grams = molarity (M) x volume (L) x molar mass (g/mol). This will give you the amount of sodium sulfate in grams needed to make the solution.
To find the grams of sodium fluoride needed, use the formula: grams = moles x molar mass. First calculate the moles by multiplying the volume (6.3 L) by the molarity (3.6 mol/L). Then multiply the moles by the molar mass of sodium fluoride (41.99 g/mol) to find the grams required. In this case, approximately 920 grams of sodium fluoride are needed.
98g
The sodium chloride mass needed is 292,2 g
262 - 266
262 - 266
Put 100 grams in a beaker and and around 500 mls of water until it dissolves, then top up the beaker to a liter. That is your 10% solution. The percentage solution is a ratio of the weight of the compound to the weight of the final solution.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
The needed mass is 0,0584 g.
To calculate the grams of sodium thiosulfate needed, first determine the molar mass of Na2S2O3 (158 g/mol). Step 1: Calculate the number of moles needed using the formula: moles = Molarity * Volume (in liters) moles = 0.025 * 2 (since 2000 ml is 2 liters) = 0.05 moles Step 2: Calculate the grams needed using the formula: grams = moles * molar mass grams = 0.05 * 158 = 7.9 grams Therefore, you would need 7.9 grams of sodium thiosulfate to make 2000 ml of a 0.025N solution.