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Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
79 grams
lets see. H20 you have 2.016 grams of hydrogen here to 16.0 grams oxygen 2.016/16.0 X 100 = 12.6% hydrogen by mass H2O2 you have the same 2.016 grams hydrogen here, but you have 32.0 grams oxygen in this molecule 2.016/32.0 X 100 = 6.3% so H2O has the higher percent by mass of hydrogen
22 grams carbon dioxide (0.5 moles)
43.2 grams of water
8.20g of carbon monoxide, how many grams of methanol will be produced?
75 g sodium chloride contain 29,75 g sodium.
Approximately 240g of hydrogen gas are produced when 120.0g of zinc metal completely reacts with hydrochloric acid.
The percentage of oxygen is 54,84 %.
43.2 grams of water
Zn + H2SO4 -> ZnSO4 + H2 I assume zinc limits? 31. 8 grams Zn (1 mole Zn/65.41 grams)(1 mole H2/1 mole Zn)(2.016 grams/1 mole H2) = 0.980 grams hydrogen gas
Ratio of O2 to H20 after balancing equation is 1:2. 1:2 1.25:x.by cross multiplication x is 2.5 Mole =mass/mr.2.5×18(mr of h20) we get 27grams.
It is not measured in grams but PPM because it is a gas.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.