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How many hosts and subnets are possible if you have an IP of 151.242.16.49 with a subnet mask of 7 bits?
Wiki User
∙ 11y ago
151.242.16.49 would be class B in a classful environment with a network
mask of 16 bits. An additional 7 bit subnet mask puts the total mask at
23 (i.e.: 255.255.254).
Subnet ID would be: 151.242.16.0
Host address range: 151.242.16.1 through 151.242.17.254
Subnet Broadcast address would be: 151.242.17.255
Wiki User
∙ 11y ago
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How many subnets and hosts per subnet can you get from the network 172.16.0.0?
There are 16 bits available; it is up to you how many of those bits you reserve for the subnet, and how many for the individual hosts within each subnet.
Given class C address with a default subnet mask How many possible subnets and usable hosts if 4 bits were borrowed?
that gives you 16 subnets with 14 usable IPs for hosts that is because one is for subnet and one for broadcas in that subnet for example: 192.168.1.0/28 - subnet number 192.168.1.15 -broadcast number usable IPs for hosts - IPs between them that is 14
Which subnet mask should be used for a class B network that is divided into subnets that will accommodate between 800 hosts and 1000 hosts?
255.255.252.0
Which subnet mask should be used for a Class B network that is divided into subnets and will accommodate between 800 hosts and 1000 hosts?
255.255.252.0
If you subdivide your class B network into 254 subnets what is the maximum number of hosts you can assign to any single subnet?
254
Which class of ip addresses offers the most flexibility for subnetting by providing for the largest number of hosts?
A class A would give you the most flexibility in terms of subnets and hosts per subnet. You could use up to 23 bits of information for subnets.
How Given a Class C network 200.1.1.0 We want 5 subnets each with 30 hosts on it. How many bits to borrow How many bits to leave What is the subnet mask ( in dot notation and in CIDR notation)?
Given a Class C network: 200.1.1.0 We want 5 subnets, each with 30 hosts on it. How many bits to borrow ? How many bits to leave? What is the subnet mask? ( in dot notation and in CIDR notation)
In a class A how many subnet bits are needed to make at least 365 useable hosts or subnets?
You would need at least 9 bits to borrow. Since 8 bits gives only 255 the additional bit will get you 256. Adding 256 + 128 gives you at least 384 subnets or hosts.
What does the subnet mask of an IP address do?
Subnet Mask provides Network & Class Identificationfor an IP Address.
If you have the following Network ID 131.112.0.0 You need at least 500 hosts per network How many networks can you create What subnet mask will you use?
If you need to divide it up into the maximum number of subnets containing at least 500 hosts each, you should use a /23 subnet mask. This will provide you with 128 networks of 510 hosts each. If you used a /24 mask, you would be limited to 254 hosts. Similarly, a /22 mask would be wasteful, allowing you 1022 hosts.
What IP addresses are subnetted A 139.233.12.12 255.255.255.0 B 10.0.0.1 255.255.255.0 C 192.168.0.1 255.255.255.0 D 190.233.17.3 255.255.255.0?
A, B and D are subnets. C is not. IP addresses A and D are both Class B subnets. Class B addresses normally have a subnet mask of 255.255.0.0. The first two bits of a class B network are always 10 which leaves 14 bits for the network prefix, thus allowing up to 16,384 separate Class B networks (including 139.233.0.0 and 190.233.0.0). The last 16 bits denote the host number thus there can be up to 65,536 hosts per network. By specifying a subnet mask of 255.255.255.0 the network can be divided into as many as 256 separate subnets each with 256 hosts. IP address B is a Class A subnet. Class A addresses normally have a subnet mask of 255.0.0.0. The first bit of a class A network is always 0, which leaves 7 bits for the network prefix, thus allowing up to 127 Class A networks (including 10.0.0.0). The last 24 bits denote the host number thus there can be up to 16,777,216 hosts per network. By specifying a subnet mask of 255.255.255.0, the hosts can be divided into as many as 65,536 separate subnets each with up to 256 hosts. IP address C is a Class C address, but is not a subnet. Class C addresses normally have a subnet mask of 255.255.255.0. The first three bits in a Class C network are always 110, leaving 21 bits for the network prefix, thus allowing up to 2,097,152 Class C networks (including 192.168.0.0). The last 8 bits denote the host number thus there can be up 256 hosts per network. To make a subnet out of a Class C address you must have a subnet mask of 255.255.255.X, where X may be 192, 224, 240, 248 or 252. That is, 2, 3, 4, 5 or 6 bits to denote the subnet and the remaining bits to denote the hosts. Thus a subnet mask of 255.255.255.192 would allow as many as 4 subnets each with up to 64 hosts, while a subnet mask of 255.255.255.240 would allow as many as 16 subnets each with up to 16 hosts. It should be noted that the maximum number of hosts is actually 2 less than the figures shown above. This is because the host address with all 0 bits is reserved for network address while the host address with all 1 bits is reserved for broadcasting.
If you have an IP address 154.16.52.16 and a subnet mask of 255.255.240.0 What are the total number of subnets possible on this network?
The easiest way to do this is to convert your subnet mask, 255.255.240.0 to binary. This subnet is a modified class B network.To find the IP address rangeTo find the IP address range, you need to compare your IP address and Subnet mask in binary.Your subnet mask in binary would be:1111 1111 . 1111 1111 . 1111 0000 . 0000 0000For reference, your IP in binary would be:1001 1010 . 0001 0000 . 0011 0100 . 0001 0000If we match up your IP to the network bits of your subnet, like so:IP:1001 1010 . 0001 0000 . 0011 0100 . 0001 0000Subnet:1111 1111 . 1111 1111 . 1111 0000 . 0000 0000..we can match the network bits with the IP address to come up with the base network address to see where your network starts.1001 1010 . 0001 0000 . 0011 0000 . 0000 0000When we convert that back to decimal, it becomes:154.16.48.0To find the highest addressable IP in our network, we take the above binary IP and change the host bits to 1.1001 1010 . 0001 0000 . 0011 1111 . 1111 1111In decimal, that becomes:154.16.63.255Your range is 154.16.48.0 to 154.16.63.255. Remember that 0 and 255 are broadcast addresses.Finding the maximum possible hosts of a given subnetIf you are just looking for the total number of hosts possible and are not concerned with what your IP range will be, you only need to convert your Subnet mask to binary.Remember that your subnet mask of 255.255.240.0 in binary would be:1111 1111 . 1111 1111 . 1111 0000 . 0000 0000Take the host bits (the zeros) and switch them to ones. Convert them from binary to decimal as one large string:Binary: 1111 1111 1111Decimal: 4,095The straight, simple answer to your question is 4,095 hosts. I can't give you a straight answer on subnets, but assuming you're talking about going from a Class B to a modified Class B network, you'd have 15 subnets with 4,095 hosts each. It is more likely that you're going from a Class C (255.255.255.0) to a modified Class B in which you now have, if you will, a negative number of subnets compared to your original network.Modifying a subnet to accomidate a given number of hostsIf you know you need, for example, 800 hosts, you can change your subnet mask bit by bit. Switching a network bit to a host bit effectively doubles the number of hosts you can have on one network. The default class C network provides 256 hosts (including broadcast). 255.255.254.0 will double the host count to 512 hosts (including broadcast). This also changes the Class C network to a modified Class B network. Switching one more bit will again double the host count to 1024 hosts (including broadcast) with a subnet mask of 255.255.252.0.
