By Avogadro's number, one mole of any substance contain 6.02 x 10^23 constituent particles.
Therefore we expect that there are 0.20 x 6.02 x 10^23 formula units of NaCl in a 0.20mol pure sample. And in each formula unit there is one singly positively charged sodium ion and a singly negatively charged chloride ion. Therefore the total number of ions is 2 x 0.20 x 6.02 x 10^23 which equates to around 2.41 x 10^23
Molarity is moles/liter, so in order to find the moles of a substance in a given volume, simply multiply molarity with volume (in liters). n=M*V
There are 10 moles present in 585 g of sodium chloride.
.73 moles
This solution contain 0,3 mol of sodium chloride.
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride
There are two moles of sodium ions in two moles of sodium chloride.
Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
Molarity is moles/liter, so in order to find the moles of a substance in a given volume, simply multiply molarity with volume (in liters). n=M*V
0,40 moles of sodium chloride contain 23,376 g.
The answer is 0,175 moles.
There are 10 moles present in 585 g of sodium chloride.
23.3772 grams are there in four tenths moles of sodium chloride
3.6
I suppose that the answers are: - 0,9 moles aluminium ions - 2,7 moles chloride ions
.73 moles
20.67 grams NaCl (1mol NaCl/58.44 g NaCl) = 0.3537 moles of sodium chloride
2.4088 x 1024 chloride ions