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Assuming the water is liquid, the specific heat is about 4.186 joule/gram·°C, so to heat 46 grams of water would take about 192.556 joules/°C.

The specific heat of ice is about 2.100 Joules/g·°C so heating 46 g of frozen water would take about 96.6 joules/°C.

The specific heat of steam is about 2.020 Joules/g·°C so heating 46 g of water vapor would take about 92.2 joules/°C.

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12y ago
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13y ago

Assuming a constant heat capacity for water over the entire temperature range of 1 calorie per gram per Kelvin (and assuming that the temperature range given means from 273.15 K to 373.15 K, the entire liquid range for water at standard pressure), it would be 4600 calories.

Since there are 4.184 Joules per calorie, that comes out to about 19 300 Joules.

q= Cg x m x change in T

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13y ago

Q=mcT

=46*4.18*100

=19228J

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6y ago

The necessary energy is 19,246 kJ.

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Q: How many joules of energy are necessary to heat sample of water with a mass of 46.0 grams from 0.0 to 100 C?
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Related questions

How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams for 0.0?

46 calories (or 192, 464 joules) for each Celsius degree.


How many joules are necessary to heat a sample of water with a mass of 46.0 grams from 0.0?

46 calories (or 192, 464 joules) for each Celsius degree.


How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams from 0.0 celsius to 100.0?

419.1 Joules are required to heat one gram of liquid water from 0.01 degC to 100 deg C. So the answer is 419.1*46 = 19278.6


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A sample of h2o with a mass of 46.0 grams has a temperature of 100 c how many joules of energy are necessary to boil the water?

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A sample of H20 with a mass of 46.0 grams has a temperature of 100 c How many joules of energy are necessary to boil the water?

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How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams from 0.0 degrees celsius to 100 degrees celsius?

42 J