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How many electrons in 1 kWh?

Updated: 8/11/2023
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12y ago

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1 kilocalorie = 4186.8 joules, and 1 joule/sec = 1 watt. So 1 kwh = 1000 x 3600 watt.secs = 3.6 x 106 joules. So answer = 4186.8/(3.6 x 106) = 1.163 x 10-3 kwh. This could also be expressed as 4.2 kwsec

You could check this directly using an electric kettle. Put in 1 liter of water (1 Kilocalorie will heat this by 1 deg celsius) Note the kettle wattage, and the cold water temperature, then note how many seconds to reach boiling temp (100 celsius). The number of kilocalories is just the temperature rise in degrees C, the number of Kwseconds is the wattage times the time to reach boiling in seconds.

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15y ago
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15y ago

The overall efficiency for thermal power plants using the Rankine cycle ranges from about 40 percent for modern coal fired plants down to about 33 percent for light water nuclear reactors, chiefly because the steam temperature at turbine inlet is much lower for nuclear plants (PWR and BWR). If we take 33 percent, this means that to produce 1 kWh at the generator the thermal input must be about 3 kWh. Now 1kW = 1000 watts = 1000 Joules/sec = 238 calories/sec (1 calorie = 4.2 Joules), so 3 kW = 714.3 calories/sec. Therefore in 1 hour = 3600 seconds, the heat energy input is 714.3 x 3600 calories or 2571.4 kilocalories.

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12y ago

1kWh = 2.3x1025 eV

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A kilowatt hour is a unit of measurement for energy. There is no direct relationship between a quantity of electrons (i.e. charge) and energy.

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