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Fats: 9.3 kcal/gm Glucose/ carbohydrates: 4.2 kcal/gm Proteins: 5 kcal/gm
How many kcal are produced when 32.0g of CH4 react? CH4+2O2->CO2+2H2O+218 kcal
The Producers get 1,000 kcal, the First-Level consumers get 100 kcal, Second-level consumers get 10 kcal and Third level gets 1 kcal.
· 1 J/(kg K) = 2.389x10-4 kcal/(kg oC) = 2.389x10-4 Btu/(lbm oF) · 1 kJ/(kg K) = 0.2389 kcal/(kg oC) = 0.2389 Btu/(lbm oF) · 1 Btu/(lbm oF) = 4,186.8 J/ (kg K) = 1 kcal/(kg oC) · 1 kcal/(kg oC) = 4,186.8 J/ (kg K) = 1 Btu/(lbm oF) Metal Specific Heat Capacity - cp (kJ/kg K)(kcal/kgoC) (Btu/lbmoF) Lead 0.13 0.031 0.03 · 1 J/(kg K) = 2.389x10-4 kcal/(kg oC) = 2.389x10-4 Btu/(lbm oF) · 1 kJ/(kg K) = 0.2389 kcal/(kg oC) = 0.2389 Btu/(lbm oF) · 1 Btu/(lbm oF) = 4,186.8 J/ (kg K) = 1 kcal/(kg oC) · 1 kcal/(kg oC) = 4,186.8 J/ (kg K) = 1 Btu/(lbm oF) Metal Specific Heat Capacity - cp (kJ/kg K)(kcal/kgoC) (Btu/lbmoF) Lead 0.13 0.031 0.03
E = mass x sp ht x Δ°t (Finding Energy)where E (Energy) or Q (Quantity of Heat), mass (g), sp ht (aka specific heat, J/g°C*[typical] or cal/g°C or kcal/g°C), and Δ°t (temperature change). Finding Temperature ChangeDivide energy by mass multiplied by specific heat. Δ°t = Energy-- Mass * sp htIn order to find the final temperature (if problem is asking for this), add or subtract the original temperature and the new temperature together.Tf = original temperature +/- new temperatureIf energy is added, the temperatures will be added together; if energy is removed, the temperatures will be subtracted.Finding MassDivide energy by specific heat multiplied by temperature change. Mass = Energy------- sp ht * Δ°tFinding Specific HeatDivide energy by mass multiplied by temperature change. Sp ht = Energy------- Mass * Δ°tConverting Form of Energy (joules, kcal, and cal)Sometimes a problem will have E be shown in cal/g°C or kcal/g°C but will be asking for Joules or even vice versa. This means a conversion has to take place. Cal --> Joules and Joules --> cal-Calories (Cal) --> Joules (J)Multiply # cal by 4.184 Joules (J).Conversion Factor# cal x 4.184 J = Joules---------- 1 cal1 cal = 4.184 Joules-Joules (J) --> Calories (Cal)Divide # Joules (J) by 4.184Conversion Factor# J x 1 cal = cal--- 4.184 J1 Joule = 0.239005736 calKcal --> Joules (J) and Joules (J) --> Kcal-Joules --> kcal (Joules --> cal --> kcal)Divide # J by # kcal multiplied by 103Conversion Factor# Joules x 1 cal - * - 1kcal = kcal---------- 4.184J -- 103 cal1 kcal = 4,184 Joules 1 Joule = 0.000239005736 kcal-Kcal --> Joules (J) (Kcal --> cal --> Joules)Multiply # kcal by 103 cal by 4.184JConversion Factor# kcal * 103 cal * 4.184J = Joules (J)----------- 1 kcal --- 1 calAnother relationship that is good to understand: 1 kcal = 1000 (103) cal 1 cal = 0.001 (10-3) kcal
carbohydrate
1 gram of fat is about 9 calories
The amount of protein (4 kcal/gram), carbohydrate (4 kcal/gram), and fat (9 kcal/gram) that is present.
7 kcal per gram
no.
There are 9 kcal in 1 gram of fat. Thus, say you were 1 lb overweight... 1 lb = 454 grams 454 grams x 9 kcal = roughly 4000 kcal THATS ALMOST TWO MARATHONS WORTH OF ENERGY! Fats contain far more energy than carbohydrates.
Fat has the highest caloric content by weight with 9 Kcal/gram while alcohol comes in second with 7 Kcal/gram. Carbohydrates and proteins carry 4 Kcal/gram. Thus the most caloric food by weight would be pure fat, such as oils and lard.
There are:4 kCal/gram for Protein4 kCal/gram for Carbohydrates9 kCal/gram for Fats (incl. saturated, monounstaurated, polyunsaturated)I've heard, though never measured, there are approx 7 kCal/gram of liquor. Obviously, this would depend on what kind of liquor (beer, wine, hard liquor, aperitif which has more sugar, etc.). Again, I have no measured proof (no pun intended - heheh)So, to answer your question, for 50g of protein we get => 50grams * 4 kCal/gram = 200 kCal. Therefore, your intake of 2000 kCal would mean that approx. 10% of your energy would be derived from the protein.HTH.
there is 4
4 calories per one gram of carbohydrates. == == A single gram of carbohydrates contains roughly four calories of energy. (Proteins also contain 4 kcal/gram; fats contain 9 kcal/gram and ethanol contains 7 kcal/gram.)
Fiber does not have any nutritional value or associated calories, because it is not absorbed by the body. It instead adds bulk and mass to the foods you eat, and it is then pushed through the digestive system. All of the fiber you take in is excreted from your body as waste. The only components of food with calculated calorie content are: fat (9 kcal in one gram) protein (4 kcal in one gram) and carbs (4 kcal in one gram). Also, alcohol has a caloric value of 7 kcal per gram.
9 kcal/gm