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15.37684 joules
15480.80
q = (42.5 g)(0.902 J/gC)(25o C - 4750o C) = - 1.8 X 105 Joules ====================negative can be ignored for absolute value, but remember the direction the heat is going.
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
21 grams through 71 degrees is 21x71 calories.
Heat is measured in unit of what...
15.37684 joules
15480.80
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
3.8 x 10^5 Joules
If by "boil" you mean have it all evaporate, that takes MUCH more energy. For example, to increase the temperature of one gram of water from 20 to 100 degrees Celsius, you need 4.2 joules/gram/degree times 80 degrees = about 336 joules; then, to evaporate all the water, you need an additional 2257 joules.
The latent heat of condensation of steam is 2260 Joules per gram (539.3 cals/g). So the amount of heat released by 12.4 g = 12.4*2260 Joules = 28,024 Joules or 6687 cals.
Approx 2940 Joules.
q = (42.5 g)(0.902 J/gC)(25o C - 4750o C) = - 1.8 X 105 Joules ====================negative can be ignored for absolute value, but remember the direction the heat is going.
Can you help
8.200 J
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.