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1 calorie increases 1 gram of water by 1 degree celsius. 4.18 Joules are needed to increase the temperature of 1 gram of water by 1 degree celsius. To reduce the 1 gram of water 1 degree celsius it would have to give off 1 calorie of energy. To calculate the energy multiply the mass in grams of water by 4.18 and by the change in temperature. The energy = 4.18 x m x change in T. The answer is in Joules. If you are using calorie as the unit of energy, replace 4.18 J by 1 C. Note that food is measured in kilocalories (Calories) not metric calories.
The air temperature needed for frozen precipitation to form is 32 degrees Fahrenheit.
A room temperature ubove 0 degrees centigrade.
It is dH = m C dT dH = 225 ( 0.21cal/gram-C) (80 C) 3780 calories your answer: 3.8kcal
Yes, usually water will melt at anything above 0 degrees celsius or boil at 100 degrees. However pressure and altitude can change the required temperature needed for boiling/melting. The higher pressure the lower temperature required and vice versa The higher altitude the less temperature needed
1 calorie increases 1 gram of water by 1 degree celsius. 4.18 Joules are needed to increase the temperature of 1 gram of water by 1 degree celsius. To reduce the 1 gram of water 1 degree celsius it would have to give off 1 calorie of energy. To calculate the energy multiply the mass in grams of water by 4.18 and by the change in temperature. The energy = 4.18 x m x change in T. The answer is in Joules. If you are using calorie as the unit of energy, replace 4.18 J by 1 C. Note that food is measured in kilocalories (Calories) not metric calories.
It takes 80 calories per gram to increase the temperature of water by one degree. 4000 * 80 * 100 = 32000000 calories.
The air temperature needed for frozen precipitation to form is 32 degrees Fahrenheit.
The needed energy is 10 calories.
A room temperature ubove 0 degrees centigrade.
A room temperature ubove 0 degrees centigrade.
8.200 J
mmmm enthalpy
quite abit
48
An increase in pressure and / or temperature would be needed to convert a sedimentary rock to a metamorphic rock.
It is dH = m C dT dH = 225 ( 0.21cal/gram-C) (80 C) 3780 calories your answer: 3.8kcal