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1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
I mole - 16g of methane is 1 mole. At STP it would occupy 22.4 liters
4 g of helium occupy 22.414 liters. So, 84.6 g of helium occupy 474.056 liters.
The volume is 64,8 L.
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
According to the ideal gas law, all gases occupy about 22.4 liters per moleof space at standard temperature and pressure, so 22.4x2.56=57.34 liters.
22.4 liters.
How many molecules are in 30 liters of methane (CH4) at STP
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.