answersLogoWhite

0


Best Answer

Suppose 25 L to be 25 kg water (almost, -0.2% at room temperature)

then divide 25,000 g by the moalr mass of H2O being 2+16=18 g/mole

you get = 1385 moles (because 1 mole = 18 grams)

User Avatar

Wiki User

14y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

14y ago

By filling in this formula with SI units of the symbols R, T, p, V you'll find the number of moles for ALL possible (ideal) gases according to Ideal Gas Law (Boyle's):

n = p*V / R*T or p*V = n*R*T n= number of moles of any gas => 25 mol (your 'known')

p= pressure of (any) gas (Pa) => 1.01325*105 Pa (=1 atm) (Standard)

V= Volume of that gas (m3) => ? (to be calculated)

R= universal Gas constant (J.mol-1.K-1 )=> 8.3145 (universal constant)

T= absolute temperature (K) => 273.15 K (Standard)

With the questioned figures:

V = nRT/p = [25*8.3145*273.15] / [1.01325*105] = 0.56035 (m3) = 560 litres for 25 moles of Ar (or any) gas at (Standard)TP

This answer is:
User Avatar

User Avatar

Wiki User

15y ago

1 mole of gas at STP occupies 22.4Lt. of space. So 25 mole will occupie 22.4*25=560lt.

This answer is:
User Avatar

User Avatar

Wiki User

11y ago

1 mole = 22.414 liters

So, 5 moles = 112.07 liters

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many liters of Argon are in5.00 moles at STP?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many moles of argon gas Ar are present in 5.6 liters of argon gas at standard conditions?

0.25 moles, approx.


How many moles of argon are in 37.9 g of argon?

moles = mass in grams / atomic weight So moles in 37.9 g or argon = 37.9 / 39.948 = 0.948 moles


How many moles of argon are found in a 5L sample of argon at STP?

Approx 0.223 moles.


How many moles of argon are in 1.67 x 1024 atoms?

1,67.1024 argon atoms is equal to 2,773 moles.


How many moles of argon are in 24.7 g of argon?

Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles


How many moles of argon in 607 g of argon?

Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.


One million argon atoms are how many moles of argon atoms?

1.7x10^-18


How many moles in 22 grams of argon?

55.64


How many liters are in 1.84 moles of helium?

1 mole occupies 22.414 liters So, 1.84 moles will occupy 41.242 liters


How many liters of naoh are in 1.3 moles of 3.42 m of naoh?

Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters


How many moles of HCl are present in 40ml of a 0.035M solution?

Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============


How many moles are in 15 mL of 2.9 M NaOH?

Molarity = moles of solute/liters of solution ( 15ml = 0.015 liters ) 2.9 M NaOH = moles NaOH/0.015 liters = 0.0435 moles of NaOH