22.4 liters will have 1 mole of Helium at STP.
So, 6 liters will have 0.23 moles
3.3
8,4 liters of nitrous oxide at STP contain 2,65 moles.
0.250 mol
4 g of helium occupy 22.414 liters. So, 84.6 g of helium occupy 474.056 liters.
At 22.4 liters a mole at STP, and the molar mass of Cl2 being 71, 17.32 g is about .242 moles. Multiply the moles by standard volume and you get 5.43 liters.
Divide by 22.4 if it is at STP
The volume is 0.887 L.
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
8,4 liters of nitrous oxide at STP contain 2,65 moles.
3.058
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
0.250 mol
1 mole = 22.414 liters So, 3.5 mole = 78.45 liters
4 g of helium occupy 22.414 liters. So, 84.6 g of helium occupy 474.056 liters.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
1 mole of gas occupies 22.4 liters at STP. 564/22.4 = 25.18 moles (2 decimal places)
At 22.4 liters a mole at STP, and the molar mass of Cl2 being 71, 17.32 g is about .242 moles. Multiply the moles by standard volume and you get 5.43 liters.
0.67 mol