(x L)((12%) = (100 L)(2%)x = 16.7 liters
Add 5 litres water.
300 ml
150 mL x 40.0 g LiNO3/100 mL solution = 60.g of solute
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
Applying the equation for a dilution (c1.V1 = c2.V2) gives4.0(mol/L)*V1(L) = 2.5(mol/L)*4.5(L) so V1 = 2.5*4.5/4.0 = 2.813 L = 2.8 litres
3.0 kg
90 ml of dextrose and 4.41 litres of water.
144liters
50liters
256 liters
50 liters
50
4.84
10 liters
50 Liters of the 60% solution.
You need 256 litres.
Add 5 litres water.