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What mass of silver chloride can be produced from 1.75L of a 0.293M solution of silver nitrate?
To determine the mass of silver chloride produced, we need to know the balanced chemical equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) that produces silver chloride (AgCl) as a precipitate. Once we have the balanced equation, we can use the stoichiometry of the reaction to determine the number of moles of AgCl produced, and then convert that to mass using the molar mass of AgCl.
How many mph equal one G force?
You can not equate miles per hour to G forces. If you were traveling at 1000 mph, for example, but at a constant speed, you would fell no extra force since you are not accelerating.
How many kilometers is 9.33 miles?
well, i mile is 1.6km, so just multiply the 9.33 by 1.6 and you have the answer! that is 14.928km. G
How many cg in a g?
There are 100 cg in a gram!
48 g 19 mg to g?
How many mg = g
How many moles of AgCl will be produced from 83.0 g of AgNO3 assuming NaCl is available in excess?
X = 0.489 moles of AgCl produced
How many moles is 573.28 g of AgCl?
Remember the equation moles = mass(g) / Mr Mr is the relative molecular mass. Refer to the Periodic Table 1 x Ag = 1 x 107.87 1 x Cl = 1 x 35.5 107.87 + 35.5 = 143.37 (Mr of AgCl) Substituting moles(AgCl) = 573.28 / 143.37 = 3.9986... ~ 4 moles (AgCl)
How many grams of silver chloride will precipitate by silver nitrate 5.85g of sodium chloride?
The answer is 14,35 g AgCl.
An impure sample of table salt that weighed 0.8421 g when dissolved in water and treated with excess AgNO3 formed 2.044 g of Ag-Cl what is the percentage of Na-Cl in the impure sample?
2.044 g AgCl / 143.33 g per mole = 0.01426 moles of AgClNaCl + AgNO3 --> AgCl + NaNO31 mole of AgCl = 1 mole of NaClThe sample contained 0.01426 moles of NaCl0.01426 moles NaCl x 58.44 g per mole = 0.8334 g NaCl0.8334 / 0.8421 = 98.97% pureI'm pretty sure this is the correct answer.
How many miles is it from Luna New Mexico to Sandia Park New Mexico?
6,000,000,000 Miles About N i G g A
What is the balanced equation for HCl plus Ag2CO3?
Ag2CO3(s) + 2HCl(aq) -> 2AgCl(s) + CO2(g) + H2O(l)
How many miles would a caravan travel to Tunis and Benin?
g
What mass in g of agcl is formed from the reaction of 75.0 ml of a 0.078 m agc2h3o2 solution with 55.0 ml of 0.109 m mgcl2 solution?
0.838g
How much AgCl is produced when 4.22 grams of AgNO3 react with 7.73 grams of AlCl3?
3.56 g 3 AgNO3 + AlCl3 --> 3 AgCl + Al(NO3)3 AgCl3 is the limiting reagent (I checked), so: 4.22 g AgNO3 * (1 mol AgNO3/169.88 g AgNO3) * (3 mol AgNO3/3 mol AgCl3) * (143.32 mol AgCl3/1 mol AgCl3) =3.56 g AgCl3See the Related Questions to the left for more information about solving stoichiometry problems of this nature.
What mass of silver chloride can be produced from 1.75L of a 0.293M solution of silver nitrate?
To determine the mass of silver chloride produced, we need to know the balanced chemical equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) that produces silver chloride (AgCl) as a precipitate. Once we have the balanced equation, we can use the stoichiometry of the reaction to determine the number of moles of AgCl produced, and then convert that to mass using the molar mass of AgCl.
How many gallons of gas would it take to drive 1657 miles?
It depends on your mileage. I'll give you the general equation, and also an example. Where G is your mileage in miles per gallon, 1657 miles / (G miles/gallon) = 1657/G gallons e.g. at 20 MPG, that's 82.85 gallons. At the US average of $2.817 per gallon, that's about $233.39.
What mass of solid agcl is obtained when 25 ml of 0.068 m agno3 reacts with excess of aqueous hcl?
See it's an easy one..!! AgNO3 + HCl -> AgCl + HNO3 100 mL of 0.068 M AgNO3 contains AgNO3 = 0.068 mol So, 25 mL of 0.068 M AgNO3 contains AgNO3 = (0.068 * 25) / 1000 = 0.0017 mol From the equation, we can see 1 mol of AgNO3 gives 1 mol of AgCl 0.0017 mol of AgNO3 gives 0.0017 mol of AgCl Amount of AgCl can be found this way.! No. of moles = given mass/ molecular mass molecular mass of AgCl = 107+35.5 = 143.5 g Therefore, Given mass = No. of moles*molecular mass = 0.0017*143.5 = 0.244g Note : In your question, you have written 0.068 "m" .. (small) m represents for Molality and (capital) M represents for Molarity..! Hope I helped.. :)
