How many mol are in 4.80 kg carbon dioxide?
4.80 kg CO2 (1000 grams/1 kg)(1 mole CO2/44.01 grams)
= 109 moles of carbon dioxide
6.23 mol carbon dioxide
b. 6.23 mol carbon dioxide
6.32 mol carbon dioxide
B. 6.23 mol carbon dioxide
6.022 * 10^21
0.35 moles carbon dioxide (6.022 X 10^23/1 mole CO2) = 2.1 X 10^23 atoms of carbon dioxide
carbon dioxide is heavier than hydrogen because the molar mass of carbon dioxide (CO2) is 44 g/mol while hydrogen (H2) is 2 g/mol.
If you have 1.4 mol of carbon before the reaction you have 1,4 mol of carbon after the reaction. If you make carbon monoxide, CO, then you need 1.4 mol of CO after the reactiion. If you make carbon dioxide, CO2, you need 1.4 mol of C2O, because you have one carbon in each molecule.
b. 6.23 mol carbon dioxide.
1.33 (g CO2) / 44 (g/mol CO2) = 0.030 mol CO2 = 0.030 mol O2
The molar mass of carbon dioxide is 44.010 g/mol as C=12 g/mol and 2O=2x16 g/moll. The mass of gas you gave is 66 g. The number of moles is 66/44=1.5
Dry ice is the solid form of carbon dioxide. CO2 has a molar mass of 44.0095 grams per mol, so there are .227 moles present.
Yes. CO2 has a weight of 44g/mol and O2 has a weight of 32g/mol.
How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?
Use dimensional analysis: (85.1 mol CO2)(1 mol CH4 / 1 mol CO2) = 85.1 mol CH4
The weigh of one cubic centimeter of carbon dioxide is 1.84 milligrams. The formula for carbon dioxide is CO2, and its molar mass is 44.0095 g/mol.
This is the carbon dioxide.
Two moles of carbon dioxide are produced.
11,2 moles carbon dioxide are obtained.
12 (one carbon) + 2*16 (two oxygens) = 48g/mol
C weighs 12.01 g/mol & O weighs 15.9996 g/mol So CO2 weighs about 44 g/mol.
The answer is 1 mol carbon.
Carbon Dioxide: CO2 C = 14.01 O = 16.00 C + 2*O= 14.01 + 2*16.00 =44.01 g/mol
There are: 165 (g) / [12.0+2*15.99] (g/mol) = 3.75 moles CO2 in 165 grams of it.
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
First a balanced chemical equation is needed. CH4 + 2O2 -> CO2 + 2H2O There is a 1:1 ratio of moles between methane and carbon dioxide so the amount of moles of methane used is the exact number of moles of carbon dioxide yielded. To determine the number of moles of methane we take the amount used and divide by methane's mass which is about 16.04 g/mol. 100g/ 16.04g/mol=6.234moles of methane. 6.234 moles of methane… Read More
Which carbon are u talking about? Carbon in coke is first oxidised to form carbon dioxide - C(s) + O2(g) -> CO2(g). Limestone is decomposed by heat to form calcium oxide and carbon dioxide. CaCO3 -> CaO(s) + CO2(g). The carbon dioxide produced in the two reactions are reduced by carbon in coke to form carbon monoxide. CO2(g) + C(s) -> 2CO(g). The carbon monoxide then reacts with iron (III) oxide in haematite to form… Read More
How many moles of carbon dioxide are produced when 19.3 mol of propane gas is burned in excess oxygen?
This is a chemical calculation. 57.9 MOLES of CO2 will formed.
How many moles of methane are produced when 82.6 moles of carbon dioxide gas react with excess hydrogen gas?
CO2+4H2 = CH4 + 2H20 (Balanced) 82.6 Moles. The Ratio is 1 Mol CH4 over 1 Mol CO2. So... 82.6 Mol CO2 * 1 Mol CH4/1 Mol CO2= 82.6 Moles of CH4
the formula for the moles of a substance is mol= grams/ grams per mol the grams per mol of carbon is 12.01 grams per mol, so... mol= 360g/12.01 grams per mol = 27.7 mol
Multiply the value of 1 mole by 5. 44 g/mol x 5 mol Mole units cancel out, leaving 220g of CO2
Glucose is C6H12O6. 1 mol of glucose is 6 mol of carbon, 12 mol of hydrogen, and 6 mol of oxygen. 1 mol Glucose x (6 mol C / 1 mol Glucose) = 6 mol C
The number of particles in a mol of a substance is the Avogadro Constant = 6.02 x 1023. For carbon-12 the value of the mol is 12 grams.
3.54 (mol) * 6.02*1023 (molecules/mol) = 2.13*1024 molecules (of any substance)
How many moles of carbon monoxide are needed to react with .500 mol of Iron III oxide to produce iron metal and carbon dioxide?
The reaction equation for the production of iron and carbon dioxide is Fe2O3 + 3 CO = 2 Fe + 3 CO2. This means that for 1/2 mole of rust, 1.5 moles of CO is needed.
Oxygen gas (2 Oxygen atoms per molecule) has a molecular weight of 32 g per mol, Carbon dioxide (1 Carbon atom + 2 Oxygen atoms per molecule) has a molecular weight of 44 g per mol, Methane (1 Carbon atom + 4 Hydrogen atoms per molecule) has a molecular weight of 16 g per mol, which that means when under the same temperature and pressure conditions, with the same amount of particles in the space… Read More
the bond energy of co2 is 799kJ/mol per bond. so, it is 1598 total.
If a typical antacid tablet contains 2 grams of sodium hydrogen carbonate how many moles of carbon dioxide should one tablet yield?
NaHCO3 = 84.007 g/mol Figure out the mole fraction = 2g / 84.007 g/mol The unit of the answer is mol, which in this context is the same as mole. Since you only have one carbon in NaHCO3 you cannot have more moles of CO2 than moles of NaHCO3.
10.84 to the 23 power
How many moles of water are produced when 3.25 moles of CO2 are formed during the combustion of methyl alcohol CH3OH?
2CH3OH + 3O2 --> 2CO2 + 4H2O is the balanced equation for the combustion of methanol. It says that you get twice as many moles of water as you get carbon dioxide. 3.25 mol x 2 = 6.50 mol
22 g = 22/44 = 0.5 mole CO2, 0.5 mol = 0.5*6.02*10+23 = 3.0*10+23 molecules
5.296 grams per mol of Carbon
The answer is 1,31 moles carbon.
Balanced equation. Butane limits and drives the reaction. (hint; balance O2 last ) 2C4H10 + 13O2 -> 8CO2 + 10H2O 1.25 moles butane (8 moles CO2/2 moles C4H10) = 5.00 moles carbon dioxide formed =========================
1.305 mol CO
What is the pressure in a 7.50L flask if 0.15 mol of carbon dioxide is added to 0.33 mol of oxygen The temperature of the mixture is 48.0C?
P=0.48*0.0821*321/7.5 P=1.6866624 atm P=170352.9024 Pa
A sample of carbon dioxide gas has a pressure of 785 torr 22.0C and a volume of 900.0 mL How many moles of carbon dioxide molecules does the container have?
Using ideal gas law...in metric units, thanks. 786 torr = 104658 Pa 900 mL = 0.0009 m3 22 C = 295.15 K R = 8.314 J/K-mol PV = nRT n = PV / RT = 104658 x 0.0009 / 8.314 x 295.15 = 0.0384 mol
A mixture of gases contains 0.25 mol oxygen gas 0.75 mol nitrogen gas and 1.50 mol carbon dioxide gas at STP The mole fraction of oxygen gas in this mixture is?
0.1 NOPE! the one above is wrong! the answer is 0.3 (I just took it on apex:] )
The number of carbon atoms which are present in 0,062 mol acetic acid HC2H3O2 is 0,747.10e23.
One time the atomic mass of carbon (12 g/mol C) = 12 Two times the atomic mass of oxygen (16 g/mol O) = 32 Adding up both (totalizing 1*12 and 2*16) gives the molar mass of CO2 = 44 g/mol CO2
So CO2 is 44g/mol. 48/44 is 1.0909091 moles. This multiplied by avagadros number is 6.57x1023 molecules. As there is 1 carbon per molecule, this also equals the number of carbon atoms
85.9 (g C) = 85.9 (g C) / 12.00 (g/mol C) = 7.158 (mol C) 7.158 (mol C)*[6.022*1023 (atoms/mol C)] = 4.31*1024 C-atoms