This will vary with the temperature, which is not stated. At a temperature of 0 degrees Celcius and pressure of 1 atmosphere, carbon dioxide has a density of 1.977 kilograms per cubic metre. Now one cubic metre of gas at 4 atmospheres is the same as four cubic metres of gas at 1 atmosphere. Thus there will be 4 x 1.977 = 7.908 kilograms of carbon dioxide in 1 cubic metre at 4 atmospheres and 0 degrees Celcius.
The molar mass of carbon dioxide is 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen). To find the number of moles in 418 grams, divide 418 grams by the molar mass of carbon dioxide. The calculation is 418 g / 44.01 g/mol = 9.50 moles of carbon dioxide.
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
The molecular weight of carbon dioxide (CO2) is 44.01 g/mol. The molecular weight of sugar (C12H22O11) is 342.3 g/mol.
CO2 carbon dioxide is heavier than oxygen.
1 mol of lithium hydroxide can absorb 1 mol of carbon dioxide. The molar mass of lithium hydroxide (LiOH) is 23.95 + 15.999 + 1.008 = 40.967 g/mol. The molar mass of carbon dioxide (CO2) is 12.011 + (2 x 15.999) = 44.011 g/mol. Therefore, 1.00 kg of lithium hydroxide can absorb 1000 g / 40.967 g/mol = 24.41 mol of CO2, which is 24.41 mol x 44.011 g/mol = 1073.1 g or 1.07 kg of gaseous carbon dioxide.
6.32 mol carbon dioxide
The molar mass of carbon dioxide is 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen). To find the number of moles in 418 grams, divide 418 grams by the molar mass of carbon dioxide. The calculation is 418 g / 44.01 g/mol = 9.50 moles of carbon dioxide.
To calculate the percentage of oxygen in carbon dioxide, you can use the molar masses of carbon and oxygen. The molar mass of carbon dioxide is 44 g/mol (with 32 g/mol from O2 and 12 g/mol from C), and the molar mass of oxygen is 32 g/mol. Therefore, the percentage of oxygen in carbon dioxide is (32 g/mol / 44 g/mol) * 100 = 72.7%.
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
The molar mass of carbon dioxide (CO2) is 44 g/mol. Carbon has a molar mass of 12 g/mol and oxygen has a molar mass of 16 g/mol. So, in 44g of CO2, there are 12g of carbon. Therefore, the percent by mass of carbon in 44g of carbon dioxide is (12g / 44g) x 100 = 27.3%.
44g/mol
First, convert the mass of carbon dioxide to grams by dividing by 1000: 220 mg = 0.22 g. Next, use the molar mass of carbon dioxide (44 g/mol) to calculate the number of moles: 0.22 g / 44 g/mol = 0.005 moles of carbon dioxide.
The total moles of gas in the mixture is 0.25 + 0.75 + 1.5 = 2.5 mol. The mole fraction of carbon dioxide gas is the moles of CO2 divided by the total moles of gas, which is 1.5 mol / 2.5 mol = 0.6. So, the mole fraction of carbon dioxide gas in the mixture is 0.6.
No, carbon dioxide is heavier than helium. Carbon dioxide has a molecular weight of about 44 g/mol, while helium has a molecular weight of 4 g/mol. This means that helium is lighter than carbon dioxide and will rise above it in the presence of air.
The molecular weight of carbon dioxide (CO2) is 44.01 g/mol. The molecular weight of sugar (C12H22O11) is 342.3 g/mol.
CO2 carbon dioxide is heavier than oxygen.
There are approximately 1.8 x 10^22 molecules in 0.03 mol of carbon dioxide. This is calculated by multiplying Avogadro's number (6.02 x 10^23) by the number of moles.