How many molecules are present in 42.0g of Cl2
9.02 X 10^23 atoms Cl2 (1mol Cl2/6.022 X 10^23) = 1.50 moles Cl2
P4+Cl2 P4+Cl2
The gram molecular mass of Cl2 is 70.906, twice the atomic mass of chlorine atoms. Therefore, 79.3 grams of Cl2 contains 79.3/70.906 or 1.12 moles, to the justified number of significant digits.
Formula: Cl2
1 mole in 70 g of Cl2
The intermolecular forces in Cl2 are London dispersion forces, which are the weakest type of intermolecular force. This occurs due to temporary fluctuations in electron distribution.
hydrogen, oxygen, nitrogen, fluorine, chlorine, bromine, iodine, astatine H2, O2, N2, F2, Cl2, Br2, I2, At2
At STP, Cl2 gas has a density of 0.0032g/mL. (Wikipedia article, "Chlorine") 0.30g Cl2 x (1mL Cl2/0.0032g) = 93.75mL Cl2
To produce 1.5 moles of chloroform (CHCl3), you would need 3 moles of chlorine (Cl2) as the reaction is 1:1 between Cl2 and CHCl3. The molar mass of Cl2 is approximately 70.9 g/mol, so 3 moles of Cl2 would be 3 * 70.9 g. Therefore, you would need approximately 212.7 grams of Cl2.
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
One molecule of Cl2 is composed of two chlorine atoms.
First, calculate the moles of Cl2 with the given mass and molar mass (70.9 g/mol). Use the mole ratio between Cl2 and PCl5 (4:1) to find the moles of PCl5 produced. So, for 56.0g Cl2, 0.790 moles of PCl5 can be produced.
Balanced equation for Sodium and Chlorine is: 2Na + Cl2 --> 2NaCl
9.02 X 10^23 atoms Cl2 (1mol Cl2/6.022 X 10^23) = 1.50 moles Cl2
Cl2 is non polar.So there are london bonds.
Cl2 is a diatomic molecule.
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 5.60 liters of Cl2 at STP would be: 5.60 L / 22.4 L/mol = 0.25 moles of Cl2.