How many molecules are present in 42.0g of Cl2
9.02 X 10^23 atoms Cl2 (1mol Cl2/6.022 X 10^23) = 1.50 moles Cl2
P4+Cl2 P4+Cl2
The gram molecular mass of Cl2 is 70.906, twice the atomic mass of chlorine atoms. Therefore, 79.3 grams of Cl2 contains 79.3/70.906 or 1.12 moles, to the justified number of significant digits.
Formula: Cl2
Cl2 + H2O = HOCl + HCl
London forces are present in chlorine molecules.
hydrogen, oxygen, nitrogen, fluorine, chlorine, bromine, iodine, astatine H2, O2, N2, F2, Cl2, Br2, I2, At2
At STP, Cl2 gas has a density of 0.0032g/mL. (Wikipedia article, "Chlorine") 0.30g Cl2 x (1mL Cl2/0.0032g) = 93.75mL Cl2
319g Cl2 are needed.
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
Cl2 is a molecule formed of 2 atoms of Chlorine.
To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.
Balanced equation for Sodium and Chlorine is: 2Na + Cl2 --> 2NaCl
9.02 X 10^23 atoms Cl2 (1mol Cl2/6.022 X 10^23) = 1.50 moles Cl2
Cl2 is non polar.So there are london bonds.
Cl2 is a diatomic molecule.
17.7