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How many moles in 79.3g CL2?
To find the number of moles in 79.3g of Cl2, first determine the molar mass of Cl2 (35.5g/mol x 2 = 71g/mol). Next, divide the given mass by the molar mass to get the number of moles (79.3g / 71g/mol = 1.12 moles of Cl2).
What is the balanced equation for CaCl2 Ca plus Cl2?
The balanced equation for the reaction between calcium (Ca) and chlorine (Cl2) to form calcium chloride (CaCl2) is: 2Ca + Cl2 -> 2CaCl2
How many grams of NaCl will be produced from 13g Cl2?
The molar ratio of Cl2 to NaCl is 1:2, so for every 1 mole of Cl2, 2 moles of NaCl are produced. To find the amount of NaCl produced from 13g of Cl2, first calculate the number of moles of Cl2 using its molar mass, then use the mole ratio to determine the moles of NaCl, and finally convert to grams of NaCl.
What is the balenced equation for F2 KCl -- KF Cl2?
The balanced equation for the reaction is: 2KF + Cl2 -> 2KCl + F2
Is Cl2 an element or a compound?
ClO4 is not a compound, it exists as ClO4-, which is a polyatomic ion called the perchlorate ion. Some positive ion such as potassium or ammonium must be present to balance the charge and form a compound.
What element are foundin nature in their elemnetal form as two atom molcules?
hydrogen, oxygen, nitrogen, fluorine, chlorine, bromine, iodine, astatine H2, O2, N2, F2, Cl2, Br2, I2, At2
What intermolecular forces are present in cl2?
London forces are present in chlorine molecules.
How many moles of cl2 are there in 7.1g of chlorine?
To find the number of moles of Cl2 in 7.1g of chlorine, you need to divide the mass of Cl2 by its molar mass. The molar mass of Cl2 is 70.9 g/mol. Therefore, 7.1g / 70.9 g/mol = 0.1 moles of Cl2.
What type of bond is in Cl2?
A covalent bond is present in Cl2. This type of bond forms when two atoms share a pair of electrons to achieve a stable electron configuration. In the case of Cl2, the two chlorine atoms share a pair of electrons to form a single covalent bond.
How Many Moles Of PCl5 Can Be Produced From 58.0 G Of Cl2 (and Excess P4)?
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
How many moles K are needed to react with 15 moles of Cl2?
H2 +Cl2---------------->2HCl Since H2 and Cl2 react in 1:1 mole ratio the number of moles of H2 reacting is equal to the number of moles of Cl2 which is equal to 0.213
How many atoms make up cl2?
Cl2 is a molecule formed of 2 atoms of Chlorine.
How many moles of PCl5 can be produced from 56.0g Cl2 and excess P4?
To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.
How many grams cl2 needed to produce 1.5 moles of chloroform?
To produce 1.5 moles of chloroform (CHCl3), you would need 3 moles of chlorine (Cl2) as the reaction is 1:1 between Cl2 and CHCl3. The molar mass of Cl2 is approximately 70.9 g/mol, so 3 moles of Cl2 would be 3 * 70.9 g. Therefore, you would need approximately 212.7 grams of Cl2.
Is Cl2 plus Cl2 London bond?
Cl2 is non polar.So there are london bonds.
How many milliliters of Cl2 gas must you have to obtain 0.30g at STP in chemistry?
You can use the ideal gas law to solve this problem. First, convert 0.30 g of Cl2 to moles. Then use the molar volume of gas at STP (22.4 L/mol) to determine the volume of Cl2 gas needed. Convert this volume to milliliters (1 L = 1000 mL) to find the answer.
How do you make cloroform?
You start with methane (CH4 ) and chlorine ( Cl2) and react them thus:- CH4 + Cl2 → CH3Cl + HCl CH3Cl + Cl2 → CH2Cl2 + HCl CH2Cl2 + Cl2 → CHCl3 + HCl
