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Q: How many molecules are in 0.25 mole of P4?
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Examples of polyatomic molecules?

S8 P4 etc. H2SO4 is also a polyatomic molecule.


How many atoms of phosphorus are present in a molecule of phosphorus?

Today are known the phosphorus molecules P2 and P4.


Phosphorus why some place denoted as P4?

Phosphorus forms individual P4 molecules. This is the standard form for white phosphorus.


A molecule of a compound?

Most molecules are compounds but not all. Some molecules such as O2 and P4 are elements.


What is the mass of 0.5 moles of P4 molecules?

This mass is 61,947 g.


How many moles of PCl5 can be produced from 56.0g Cl2 and excess P4?

To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.


How many atoms are there in the molecule of phospherous P4?

The answer is four. The molecular formula of any element or compund gives you the number of atoms of each element in a molecule. For phosphorus the most common form is P4 . The molecules are tetrahedral with a P atom at each apex.


Is P4 molecular?

Yes, phosphorus consists of P4 molecules which are arranged in molecular crystals bound by van der Waals forces. Each phosphorus atom is bound to three others in a tetrahedron.


How many moles of PCl5 can be produced from 24 grams of P4?

Assuming that you are combining the P4 with Cl2 and there is a suffiecient quantity of Cl2 for the P4 to completely react, you will first need a balanced equation which is P4 + 10Cl2 -> 4PCl5. From there, it's mostly stoichiometry. Take the 24g of P4, divide by the molar mass (123.88g/mol) to get the number of moles of P4 that you have (0.194). You then have to convert, using the balanced equation, from moles of P4 to moles of PCl5, in this case multiplying by 4. That will give you the number of moles of PCl5. The stoichiometry should look something like this 24.0 g P4 x (1 mol P4/123.88g P4) x (4 mol PCl5/1 mol P4).


How many phosphorus atoms are in a molecule of P4?

76


How do you balance redox H2O Cl2 P4 - POCl3 HCl?

P4+Cl2 P4+Cl2


What mass of PCl 5 will be produced from the given masses of both reactants?

What mass of will be produced from the given masses of both reactants? 28.0 g/P4 / 123.9 g/P4 = 0.2260 moles/ P4 0.2260 moles /P4 * 4 moles PCl5/1 mole/P4=0.904 moles/PCl5 54.0 g/Cl2 / 70.9 g/Cl2 = .7616 moles/Cl2 .7616 moles / Cl2 *4 moles PCl5/10 moles Cl2=.30 This is about limiting reagents You need to use 2P + 5Cl2 --> 2PCl5 [or P4 + 10Cl2 --> 4PCl5 if you prefer] that tells you that 2P = 62g needs 5Cl2 = 355g Cl2 to react 69.3g