4.5 moles
4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
To find the mass of fluorine produced, first calculate the mass of sodium fluoride: 27.7 grams of sodium / (1 part sodium / 1 part sodium fluoride) = 27.7 grams of sodium fluoride Now, since the ratio of sodium to fluorine in sodium fluoride is 1:2 (1 part sodium to 2 parts fluorine), the mass of fluorine is 27.7 grams / 2 = 13.85 grams.
Multiply the number of moles by the molecular weight.
To find the number of grams in 4.5 moles of sodium fluoride, you would multiply the number of moles by the molar mass of sodium fluoride. The molar mass of sodium fluoride (NaF) is approximately 41 g/mol. So, 4.5 moles x 41 g/mol = 184.5 grams of sodium fluoride.
To find the grams of sodium fluoride needed, use the formula: grams = moles x molar mass. First calculate the moles by multiplying the volume (6.3 L) by the molarity (3.6 mol/L). Then multiply the moles by the molar mass of sodium fluoride (41.99 g/mol) to find the grams required. In this case, approximately 920 grams of sodium fluoride are needed.
To find the number of moles in 4.06 x 10^25 molecules of sodium fluoride, you would divide the number of molecules by Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol. Therefore, 4.06 x 10^25 molecules / 6.022 x 10^23 molecules/mol ≈ 67.5 moles of sodium fluoride.
The mass of sodium is 22,91.10e-23 g.
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
To find the total amount of sodium fluoride needed, first convert 110 μg to grams (110 μg = 0.00011 g). Then multiply the amount per tablet by the number of tablets: 0.00011 g x 600000 = 66 grams of sodium fluoride are needed to make 600000 tablets.
There are approximately 0.5 moles of NaCl in 29.22 grams. This would be 3.01 x 10^23 molecules of NaCl.
One atom of sodium and one atom of fluorine.
There are 2.54 grams of sodium in 1 gram of sodium carbonate.