The formula mass of sodium fluoride, NaF is 23.0+19.0=42.0
Mass of 4.5mol of NaF = 4.5 x 42.0 = 189g
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
To find the grams of sodium fluoride needed, use the formula: grams = moles x molar mass. First calculate the moles by multiplying the volume (6.3 L) by the molarity (3.6 mol/L). Then multiply the moles by the molar mass of sodium fluoride (41.99 g/mol) to find the grams required. In this case, approximately 920 grams of sodium fluoride are needed.
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
By stoichiometry, 2 moles of sodium carbonate will produce 2 moles of sodium chloride. The molar mass of sodium chloride is approximately 58.44 g/mol, so 2 moles would weigh about 116.88 grams.
To find the number of moles, you first need to determine the molar mass of calcium fluoride, which is 78.07 g/mol. Then, divide the given mass by the molar mass: 12.8 g / 78.07 g/mol = 0.164 moles. Therefore, there are 0.164 moles in 12.8 g of calcium fluoride.
4.5 moles
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
To find the grams of sodium fluoride needed, use the formula: grams = moles x molar mass. First calculate the moles by multiplying the volume (6.3 L) by the molarity (3.6 mol/L). Then multiply the moles by the molar mass of sodium fluoride (41.99 g/mol) to find the grams required. In this case, approximately 920 grams of sodium fluoride are needed.
4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
Multiply the number of moles by the molecular weight.
23.3772 grams are there in four tenths moles of sodium chloride
To find the mass of fluorine produced, first calculate the mass of sodium fluoride: 27.7 grams of sodium / (1 part sodium / 1 part sodium fluoride) = 27.7 grams of sodium fluoride Now, since the ratio of sodium to fluorine in sodium fluoride is 1:2 (1 part sodium to 2 parts fluorine), the mass of fluorine is 27.7 grams / 2 = 13.85 grams.
The molar mass of sodium hydrogen carbonate is 84 grams per mole, therefore 0.5 moles of it weighs 42 grams.
55.0 moles of sodium are equal to 1 264,44 g.
0,40 moles of sodium chloride contain 23,376 g.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
22.98977 grams.