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The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
78 g
The ratio in aluminum chloride is 1:3 aluminum to chloride ( AlCl3 or Al2Cl6 )
Lithium chloride is not transformed in calcium chloride.
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
266,86 g aluminium chloride are obtained.
29
44.26% Aluminium Chloride is Aluminium.So there are 11.06g is aluminium in 25g.
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
The answer is: approx. 327 g.
78 g
3.5 X 10^24
The ratio in aluminum chloride is 1:3 aluminum to chloride ( AlCl3 or Al2Cl6 )
17.9 grams
Silver chloride - AgClAg (107.89 grams) + Cl (35.45 grams) = 143.34 grams
Aluminum is 3+ and chloride is 1-. So, you need 3 chloride ions to neutralize 1 aluminum ion.
Lithium chloride is not transformed in calcium chloride.