C3h6o + 4o2 -----> 3co2 + 3h2o
Nope, combustion
C-carbon H-hydrogen O-oxygen Three different elements.
1. 6 carbon dioxide molecules combine with six 5-carbon molecules forming twelve 3-carbon molecules.2. The 12 3-carbon molecules are converted into high-energy forms.3. 2 of the 12 3-carbon molecules are removed and the plant uses them to produce sugars, lipids, amino acids, and other compounds.4. The 10 3-carbon molecules What_are_the_four_steps_in_the_Calvin_cycleback into six 5-carbon molecules, which combine with 6 more carbon dioxide molecules.The process starts over.
1 x 1024 molecules
The answer is: C3H8 + 5O2 3CO2 + 4H2O
"CO2" is carbon dioxide. The three in front indicates that there are three molecules of the compound. Usually you wouldn't see 3CO2 on its own, you would just see CO2 or carbon dioxide. The only time a coefficient (the three in this case) is given is when an equation is being balanced.
C3H8 + 5O2 >> 3CO2 + 4H2O ( and, of course, energy )
C3h6o + 4o2 -----> 3co2 + 3h2o
C3h8+ 5o2---> 3co2+ 4h2o
There is no answerable version of this question, which asks about a certainequation not shown in the question.Further, there is no answerable form of the question. Generally the element that has the largest number of molecules depends on "valence" but all molecules in a given equation could have exactly the same number. There is no way to know.There are already questions that ask about this in answerable forms.
Coefficients :)
C3H8 + 5O2 --> 3CO2 + 4H2O
2(Fe2O3)+3C ==> 4Fe + 3CO2
Nope, combustion
C-carbon H-hydrogen O-oxygen Three different elements.
1. 6 carbon dioxide molecules combine with six 5-carbon molecules forming twelve 3-carbon molecules.2. The 12 3-carbon molecules are converted into high-energy forms.3. 2 of the 12 3-carbon molecules are removed and the plant uses them to produce sugars, lipids, amino acids, and other compounds.4. The 10 3-carbon molecules What_are_the_four_steps_in_the_Calvin_cycleback into six 5-carbon molecules, which combine with 6 more carbon dioxide molecules.The process starts over.