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It depends how much sulphur dioxide you have. If you mean how many atoms does a sulphur dioxide molecule have the answer is 3. 1 sulphur and 2 oxygen atoms.
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∙ 11y ago
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∙ 13y agoThere are eight Atoms in a molecule of sulphur (S8).
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∙ 12y agoThere are 8 molecules in sulphur. They are S8
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∙ 12y agoone mole of any stuff has Avogadro's number of parts of that stuff, that's 6.02 * 10^23 pts/mole
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∙ 11y ago2 moles sulfur dioxide (6.022 X 1023/1 mole SO2)
= 1 X 1024 molecules of sulfur dioxide
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∙ 15y ago3 S II O
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∙ 12y ago6
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How many molecules of sulfur dioxide are present in 72 g of the substance?
72 grams SO2 (1 mole SO2/64.07 grams)(6.022 X 1023/1 mole SO2) = 6.8 X 1023 molecules of sulfur dioxide ============================
How many molecules are in 0.65 moles of sulfur dioxide?
Find: m molecules from 0.65 mole of SO2Link: 6.02 × 1023 formula units ↔ 1 moleConvert: 6.02 × 1023 molecules ↔ 1 moleProportion: There are 6.02 × 1023 molecules in 1 mole. Hence, in 0.65 mole:m = 0.65 × (6.02 × 1023)m = 3.91 × 1023Answer: 3.91 x 1023 molecules are in 0.65 mole of SO2.
What is the mass prcent of oxygen in sulfur dioxide?
A sulfur dioxide has one sulfur atom and two oxygen atoms. Therefore, considering a mole of sulfur dioxide (64g); there is 32g of sulfur and 32g of oxygen. Hence the mass percent of oxygen is 50%.
How many moles of SO2 is present in 0.45 grams of sulfur dioxide?
1 mole SO2 = 64.064g SO2 0.45g SO2 x 1mol SO2/64.064g SO2 = 0.0070 mole SO2
What is the number of moles of sulfur in sulfur trioxide?
There is 1 molecule of sulfur in sulfur trioxide so there is 1 mole of sulfur in 1 mole of sulfur trioxide
How many molecules of sulfur dioxide are present in 72 g of the substance?
72 grams SO2 (1 mole SO2/64.07 grams)(6.022 X 1023/1 mole SO2) = 6.8 X 1023 molecules of sulfur dioxide ============================
What does a mole of zinc and sulfur dioxide molecules have in common?
A mole of any compound or element has 6,022 140 857(74).10e23 molecules or atoms.
How many molecules are in one mole of sulfur molecule?
6.022*10^23
How many moles of oxygen atoms are present in one half mole of carbon dioxide molecules?
Since each mole of carbon dioxide molecules contains two moles of oxygen atoms, as indicated by the formula CO2 for carbon dioxide, half a mole of carbon dioxide will have one mole of oxygen atoms.
How many molecules are in 0.65 moles of sulfur dioxide?
Find: m molecules from 0.65 mole of SO2Link: 6.02 × 1023 formula units ↔ 1 moleConvert: 6.02 × 1023 molecules ↔ 1 moleProportion: There are 6.02 × 1023 molecules in 1 mole. Hence, in 0.65 mole:m = 0.65 × (6.02 × 1023)m = 3.91 × 1023Answer: 3.91 x 1023 molecules are in 0.65 mole of SO2.
How many atoms are in 37.14 grams of sulfur dioxide?
Sulfur has relative atomic mass of 32 and oxygen have that of 16. The molar mass of sulfur dioxide is 64 grams per mole. Therefore there is approximately 0.58 moles (37.14/64) of sulfur dioxide in given weight.
What is the mass prcent of oxygen in sulfur dioxide?
A sulfur dioxide has one sulfur atom and two oxygen atoms. Therefore, considering a mole of sulfur dioxide (64g); there is 32g of sulfur and 32g of oxygen. Hence the mass percent of oxygen is 50%.
How many molecules are in 2.10 moles of carbon dioxide?
2.10 moles carbon dioxide (6.022 X 1023/1 mole CO2) = 1.26 X 1024 molecules of carbon dioxide ==============================
How many carbon dioxide molecules are there in 7.30 moles of carbon dioxide?
7.30 moles carbon dioxide (6.022 X 10^23/1 mole CO2) = 4.40 X 10^24 molecules of carbon dioxide
How many moles are equivalent to 3.75X10 to the 24Th power molecules of carbon dioxide?
3.75 X 1024 molecules carbon dioxide (1 mole CO2/6.022 X 1023) = 6.23 moles carbon dioxide ==================
How many sulfur molecules are in sodium sulfide?
We refer to "molecules" of sodium sulfate as formula units. The formula is Na2SO4. The molar mass is 142 g/mole. And sulfur (S) is 32 out of the entire 142 g. So, percent sulfur is 32/142 (x100%) = 22.5%
How many carbon dioxide molecules are there in 6.82 moles of carbon dioxide?
Multiply by avagadro constant. It is equals to 6.022*1^23
