There are no molecules.There are five atoms.
Take the molecular mass.Divide given mass by it.Then multiply by 6.022 × 10^23
You would multiply the number of grams x Avogadro's number=number of molecules: (21.6g) X (6.022x10^23)= 1.301x10^25 molecules
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
How many molecules are in 30 liters of methane (CH4) at STP
1,25 grams of CH4 contain 0,156696.10e23 atoms.
Molecular mass of CH4 = 12.0 + 4(1.0) = 16.0 Amount of CH4 = 64.5/16.0 = 4.03mol 1mol of CH4 contains 6.02 x 1023 molecules (avogadro constant). Therefore 4.03mol of CH4 contains 4.03 x 6.02 x 1023 = 2.43 x 1024 molecules.
One mole is equal to 6.022 x 1023 of anything. In this case, we are looking for molecules. So 1 mole=6.022 x 1023 molecules. We have 2.3 moles, so we want to know how many molecules are there. 2.3 mol CH4 x 6.022x1023 molecules CH4 / mol CH4 = 1.38x1024 molecules of CH4
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
Divide 96 by molecular mass.So the answer is 6mol
Find out the percentage of hydrogen in the molar mass of methane. Molar mass of CH4: C = 1 * 12.01 g = 12.01 g H = 4 * 1.01 g = 4.04 g Total = 16.05 g 4.04 g/16.05 g * 100% = 25.171% 0.25171 * 20 g = 5.0342 g There are about 5.03 grams of hydrogen in 20 grams of methane gas.
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
nh3-nh3 because they are both polar molecules
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.