3.34E22
The number of molecules is 2,308.10e23.
2H2 + O2 ==> 2H2O1.95x10^24 H2 molecules x 2 molecules H2O/2 molecules H2 x 1 mole H2O/6.02x10^23 molecules = 3.24 moles H2O x 18 g/mole = 58.3 g H2O
36 g (6.02 x 1023 at / 12.01 g) = 1.8 x 1024atoms
[10.0(g) / 18.0(g/mol H2O)] * 6.02.10+23(molecules/mol) = 3.34.10+23 molecules in 10 g of H2O(never mind the physical state: solid, liquid, vapor; it's all 10.0 grams of it)
3.34E22
The number of molecules is 2,308.10e23.
2H2 + O2 ==> 2H2O1.95x10^24 H2 molecules x 2 molecules H2O/2 molecules H2 x 1 mole H2O/6.02x10^23 molecules = 3.24 moles H2O x 18 g/mole = 58.3 g H2O
Assuming a density of 1.0 g/ml for water, then 10 ml H2O = 10 g10 g H2O x 1 mol/18 g = 0.5555 moles H2O0.5555 moles x 6.02x10^23 molecules/mole = 3.34x10^23 molecules of H2O in 10 ml
36 g (6.02 x 1023 at / 12.01 g) = 1.8 x 1024atoms
To find this out you simply times 17 by avogadros number 17mol H2O X 6.022x10^23 molecules of anything/mol of anything mols cancel and you are left in molecules of H2O the answer is 1.024x10^25 molecules H2O
[10.0(g) / 18.0(g/mol H2O)] * 6.02.10+23(molecules/mol) = 3.34.10+23 molecules in 10 g of H2O(never mind the physical state: solid, liquid, vapor; it's all 10.0 grams of it)
Divide mass of 27 g H2O by its molar mass of 18.0 g.mol−1 H2O and you get the number of moles: 1.5 mole H2O
95.2 grams water (1 mole H2O/18.016 grams)(6.022 X 10^23/1 mole H2O) = 3.18 X 10^24 molecules of water
Atomic mass- 1.01Formula- grams × (6.02 × 1023) / atomic mass = number of atoms1.00 grams H × (6.02 × 1023) / 1.01 grams = 5.96 × 1023 atoms of hydrogen
How many formula units make up 2.00 g of magnesium chloride
0.056 mole