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95.2 grams water (1 mole H2O/18.016 grams)(6.022 X 10^23/1 mole H2O) = 3.18 X 10^24 molecules of water
step 1; find # of moles 1.00*10^24 molecules x 1 mole of 6.02*10^23 molecules = 8.52*10^17 mole of H2O ( 1.0010*10^24 x 6.02*10^23 ) = 8.52*10^17 step 2 ; mass of H2O 8.52*10^17 mole x 18.02 grams per mole = 1.18*10^17 g H2O ( 8.52*10^17 x 18.02 ) = 1.18*10^17
First write out the equation and balance it. Then look at the ratio of C8H10 to CO2 produced in the reaction (hint: use molecular weights). For example: 2A = 1B + 1C where A =4, B=5, and C=3 so, for every 8g of A you get 5g of B 20g of B will yield 20 x 5/8 = 12.5g
A mole of water is about 18 grams or 18 milliliters of water.A mole of water has 6.022 x 10^23 water molecules. And 10.0 grams of has 3.345 × 10^23 water molecules. And there are 3 total atoms in water molecules, which is H2O. (3.34 × 10^23)*3=1.006 × 10^24 Which means that 1x10^24 atoms are in 10.0 grams of water.
You must mean; how many grams of O ( one atom oxygen ) 1.23 X 10^24 molecules H2O (1 mole H2O/6.022 X 10^23)(1 mole O/1 mole H2O)(16 grams/1 mole O) = 32.7 grams of oxygen
Formula mass / Formula weight / Molecular mass / Molecular weight of H2O = (1*2) + 16 = 18g 1 mol of H2O = 18g H2O 1 mol of H2O = 6.023 * 10^23 molecules In 18g H2O there are 6.023 * 10^23 molecules. So, In 1g H2O there are (6.023 * 10^23) / 18 molecules = 3.346 * 10^22 molecules Therefore, In 7.3g H2O there are (3.346 * 10^22) * 7.3 molecules = 2.443 * 10^23 molecules Ans: 2.443 * 10^23 molecules
95.2 grams water (1 mole H2O/18.016 grams)(6.022 X 10^23/1 mole H2O) = 3.18 X 10^24 molecules of water
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O=18.0 grams235 grams H2O / (18.0 grams) = 13.1 moles H2O
The molar mass of H2O =(2 atoms H x 1.00794g/mol H) + (1 atom O x 15.9994g/mol O) = 18.0152g/mol H2O1 mole of H2O = 18.0152g H2O1 mole of H2O molecules = 6.022 x 1023 molecules H2OConvert molecules to moles.5.00 x 102g H2O molecules x (1mole H2O/6.022 x 1023 molecules H2O) =8.31 x 10-22 mole H2OConvert moles to grams.8.31 x 10-22 mole H2O x (18.0152g H2O/1mole H2O) = 1.50 x 10-20g H2OAnswer: The mass in grams of 5.00 x 102g H2O molecules = 1.50 x 10-20g H2O
36 g (6.02 x 1023 at / 12.01 g) = 1.8 x 1024atoms
6 grams water (1 mole H2O/18.016 grams)(6.022 X 10^23/1 mole H2O) = 2.0 X 10^23 molecules of water
step 1; find # of moles 1.00*10^24 molecules x 1 mole of 6.02*10^23 molecules = 8.52*10^17 mole of H2O ( 1.0010*10^24 x 6.02*10^23 ) = 8.52*10^17 step 2 ; mass of H2O 8.52*10^17 mole x 18.02 grams per mole = 1.18*10^17 g H2O ( 8.52*10^17 x 18.02 ) = 1.18*10^17
There are four molecules of water in 4H2O. One molecule of water is written as H2O. The subscript 2 tells you that there are two H(hydrogen) atoms. Since there is no subscript after the O there is one O(oxygen) atom. Now back to 4H2O. The coefficient 4 tells you there are four molecules of H2O. Therefore there are eight H(hydrogen) atoms and four O(oxygen) atoms.
Atomic mass- 1.01Formula- grams × (6.02 × 1023) / atomic mass = number of atoms1.00 grams H × (6.02 × 1023) / 1.01 grams = 5.96 × 1023 atoms of hydrogen
First write out the equation and balance it. Then look at the ratio of C8H10 to CO2 produced in the reaction (hint: use molecular weights). For example: 2A = 1B + 1C where A =4, B=5, and C=3 so, for every 8g of A you get 5g of B 20g of B will yield 20 x 5/8 = 12.5g
A mole of water is about 18 grams or 18 milliliters of water.A mole of water has 6.022 x 10^23 water molecules. And 10.0 grams of has 3.345 × 10^23 water molecules. And there are 3 total atoms in water molecules, which is H2O. (3.34 × 10^23)*3=1.006 × 10^24 Which means that 1x10^24 atoms are in 10.0 grams of water.
The molecular mass of H2O is 2(1.0) + 16.0 = 18.0Amount of H2O = 3/18.0 = 0.167mol The Avogadro's number is 6.02 x 10^23 Number of molecules of H2O in 3g sample = 0.167 x 6.02 x 10^23 = 1.00 x 10^23