1 mole LiCl = 42.394g = 6.022 x 1023 formula units (not molecules because it is ionic) 127.17g LiCl x 6.022 x 1023 formula units/42.394g = 1.8064 x 1024 formula units
Assuming the question refers to LiCl (Lithium chloride) which has a molecular weight 42.39. Avogadro's constant states there are 6.022 141 79x1023 molecules per mole 9.34 g LiCl is 9.34/42.39 mole (0.220 mole) LiCl The number of molecules is therefore 6.022 141 79x1023x 0.220 =1.326x1023 molecules
1.64×1022 molecules
The number of molecules is 6,3985.10e24.
The number of water molecules is 16,728.10e23.
6.02 x 1023
1 mole LiCl = 42.394g = 6.022 x 1023 formula units (not molecules because it is ionic) 127.17g LiCl x 6.022 x 1023 formula units/42.394g = 1.8064 x 1024 formula units
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
Assuming the question refers to LiCl (Lithium chloride) which has a molecular weight 42.39. Avogadro's constant states there are 6.022 141 79x1023 molecules per mole 9.34 g LiCl is 9.34/42.39 mole (0.220 mole) LiCl The number of molecules is therefore 6.022 141 79x1023x 0.220 =1.326x1023 molecules
The formula mass of the ionic compound lithium chloride, LiCl is 6.9 + 35.5 = 42.4.Amount of LiCl = 98.2/42.4 = 2.32molThere are 2.32 moles of formula unit in a 98.2g pure sample of LiCl.To get the numerical number, multiply the quantity in moles by the Avogadro's constant.
1.64×1022 molecules
1.51 x 10 ^23 molecules
2.05×1022 molecules
The number of molecules is 6,3985.10e24.
The number of water molecules is 16,728.10e23.
The answer is 1,357.10 ex.23 molecules.