To determine the number of molecules in a sample of LiCl, we need to first calculate the number of moles using the molar mass of LiCl (42.39 g/mol). Next, we use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, there are approximately (127.17 \text{ g} / 42.39 \text{ g/mol} \approx 3 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} ≈ 1.8 \times 10^{24}) molecules of LiCl in 127.17 g.
Assuming the question refers to LiCl (Lithium chloride) which has a molecular weight 42.39. Avogadro's constant states there are 6.022 141 79x1023 molecules per mole 9.34 g LiCl is 9.34/42.39 mole (0.220 mole) LiCl The number of molecules is therefore 6.022 141 79x1023x 0.220 =1.326x1023 molecules
To calculate the number of molecules in a sample, you need to know the mass of the sample and the molar mass of the compound. Then you can use Avogadro's number (6.022 x 10^23) to convert from grams to molecules.
To calculate the number of molecules in a sample of dimethylmercury, you would first need to determine the number of moles in the sample using the molar mass of dimethylmercury. Then you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules.
A 50g sample of H2O contains approximately 2.78 x 10^24 molecules of water. This is calculated by first converting the mass to moles, then using Avogadro's number to determine the number of molecules present in that many moles of water.
To find the number of molecules of LiCl in a 127.17 g sample, you first need to convert the mass of LiCl to moles using its molar mass. Then, use Avogadro's number (6.022 x 10^23) to convert moles to molecules. Calculate the number of molecules of LiCl in the sample using these values.
To determine the number of molecules in a sample of LiCl, we need to first calculate the number of moles using the molar mass of LiCl (42.39 g/mol). Next, we use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, there are approximately (127.17 \text{ g} / 42.39 \text{ g/mol} \approx 3 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} ≈ 1.8 \times 10^{24}) molecules of LiCl in 127.17 g.
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
Assuming the question refers to LiCl (Lithium chloride) which has a molecular weight 42.39. Avogadro's constant states there are 6.022 141 79x1023 molecules per mole 9.34 g LiCl is 9.34/42.39 mole (0.220 mole) LiCl The number of molecules is therefore 6.022 141 79x1023x 0.220 =1.326x1023 molecules
To find the number of moles in 0.550 grams of LiCl, divide the mass by the molar mass of LiCl, which is approximately 42.4 g/mol. 0.550 g LiCl / 42.4 g/mol LiCl ≈ 0.013 mol LiCl. Therefore, the student has approximately 0.013 moles of LiCl.
To calculate the number of molecules in a sample, you need to know the mass of the sample and the molar mass of the compound. Then you can use Avogadro's number (6.022 x 10^23) to convert from grams to molecules.
The answer is 1,357.10 ex.23 molecules.
To calculate the number of molecules in a sample of dimethylmercury, you would first need to determine the number of moles in the sample using the molar mass of dimethylmercury. Then you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules.
3
1.24*10^22
1.814*1022