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A student weighed 0.550 grams of lithium chloride LiCl to use in a reaction How many moles is this?
To find the number of moles in 0.550 grams of LiCl, divide the mass by the molar mass of LiCl, which is approximately 42.4 g/mol. 0.550 g LiCl / 42.4 g/mol LiCl ≈ 0.013 mol LiCl. Therefore, the student has approximately 0.013 moles of LiCl.
How many formula units are there in 98.2g of LiCl?
The formula mass of the ionic compound lithium chloride, LiCl is 6.9 + 35.5 = 42.4.Amount of LiCl = 98.2/42.4 = 2.32molThere are 2.32 moles of formula unit in a 98.2g pure sample of LiCl.To get the numerical number, multiply the quantity in moles by the Avogadro's constant.
How many types of molecules with different masses exist in a sample of chlorine gas if the same exists entirely as diatomic molecules?
In a sample of chlorine gas, all molecules are diatomic composed of two chlorine atoms. This means there is only one type of molecule in the sample, with a molecular formula Cl2.
How many loaned pairs of electrons does LiCl have?
LiCl does not have any loaned pairs of electrons. In LiCl, lithium donates one electron to chlorine to form an ionic bond, leading to a full outer shell for both elements.
A student weighed 0.550 g of lithium chloride LiCl to use in a reaction How many moles is this?
To calculate the number of moles of lithium chloride (LiCl) in 0.550 g, you need to divide the mass by the molar mass of LiCl. The molar mass of LiCl is approximately 42.39 g/mol (6.94 g/mol for Li and 35.45 g/mol for Cl). Therefore, 0.550 g of LiCl is approximately 0.013 moles.
How many molecules of LiCl are in a 127.17g sample?
To calculate the number of molecules of LiCl in a 127.17g sample, you first need to determine the number of moles of LiCl in the sample using the molar mass of LiCl (6.94g/mol for Li and 35.45g/mol for Cl). Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
How many molecules are in LiCi are in a 127.17 g sample?
To determine the number of molecules in a sample of LiCl, we need to first calculate the number of moles using the molar mass of LiCl (42.39 g/mol). Next, we use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, there are approximately (127.17 \text{ g} / 42.39 \text{ g/mol} \approx 3 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} ≈ 1.8 \times 10^{24}) molecules of LiCl in 127.17 g.
How many formula units of LiCl are in a 127.17 g sample?
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
How many formula units of LiCl are in 127.17 g sample?
127.17 g LiCl x 1 mol/42.4 g x 6.02x10^23 Form.Units/moles = 1.81x10^24 Formula Units.
How many molecules are there in 9.34 grams of water?
Assuming the question refers to LiCl (Lithium chloride) which has a molecular weight 42.39. Avogadro's constant states there are 6.022 141 79x1023 molecules per mole 9.34 g LiCl is 9.34/42.39 mole (0.220 mole) LiCl The number of molecules is therefore 6.022 141 79x1023x 0.220 =1.326x1023 molecules
A student weighed 0.550 grams of lithium chloride LiCl to use in a reaction How many moles is this?
To find the number of moles in 0.550 grams of LiCl, divide the mass by the molar mass of LiCl, which is approximately 42.4 g/mol. 0.550 g LiCl / 42.4 g/mol LiCl ≈ 0.013 mol LiCl. Therefore, the student has approximately 0.013 moles of LiCl.
How many molecules are in sample 57.45 CF2Cl2?
To calculate the number of molecules in a sample, you need to know the mass of the sample and the molar mass of the compound. Then you can use Avogadro's number (6.022 x 10^23) to convert from grams to molecules.
How many molecules are contained in a 5.20 g sample of dimethylmercury?
The answer is 1,357.10 ex.23 molecules.
How many molecules are contained in a 4.15-g sample of dimethylmercury?
To calculate the number of molecules in a sample of dimethylmercury, you would first need to determine the number of moles in the sample using the molar mass of dimethylmercury. Then you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules.
How many moles of molecules does a 36g sample of carbon briquets contain?
3
How many molecules are contained in a g sample of dimethylmercury?
1.24*10^22
How many molecules are contained in a 6.95 g sample of dimethylmercury?
1.814*1022
