The chemical formula for Aspartame is C14H18N2O5. The molar mass is 294.30 g mol−1. If we have 2.50 mg of aspartame, we have 8.495 x 10^-6 mol of aspartame. There are 6.022 x 10 ^23 molecules in a mole so we have 5.116 x 10 ^18 aspartame molecules. There are 18 H atoms per aspartame molecule so there are 9.028 x 10^19 H atoms present in 2.50 mg of aspartame.
Roughly 1.023x10^22 molecules of aspartame or 10,230,000,000,000,000,000,000
2.50 grams C14H18N2O5 (1 mole C14H18N2O5/294.304 grams)(18 moles H/1 mole C14H18N2O5)(6.022 X 1023/1 mole H) = 9.21 X 1022 atoms of aspartame
The amount of hydrogen atoms that are present in 2.00 mg of aspartame are 2.167*10^22.
The number of hydrogen atomst in 2,43 g of aspartame is 108,51285.10e23.
The chemical formula for aspartame is C14H18N2O5. The molar weight is 294.3 grams/mol, so there are .00001699 moles of aspartame. Using Avogadro's number, there are 1.023 E19 molecules, each containing 18 hydrogen atoms. So there are 1.842 E20 atoms of hydrogen.
There are 17 micromoles in 5.00mg of aspartame. 5.00mg has a molecular weight of 294.303 g/mol. Aspartame is composed of carbon, hydrogen, nitrogen and oxygen. The chemical formula for aspartame is C14H18N2O5. The molar mass is 294.30 g mol−1. There are 6.022 x 10 ^23 molecules in a mole
no of moles in aspartame =mass/molar mass=1.2/294=0.00408mols no of molecules=0.00408* avagadros no.=0.00408*6.022*10^23=0.02456*10^23 no. of atoms =no.of molecules*2(coz 2 atoms of nitrogen are present)=0.02456*10^23*2
aspartame is a synthetic sweetening agent used in Pharmaceutical preparations and its Mol. Mass is 294.3 g/mol
Aspartame
The answer is 0,166.10e23 molecules.
How many molecules are present in 42.0g of Cl2
12 molecules of carbon 24 of hydrogen 12 of oxygen