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Here we're going to assume none of the acetylene gets a chance to escape into the atmosphere. Since it's lighter than air, we'll have to...I don't know, react it in a jar or something.

We know the reaction we're going for is:

C2H2 + n(O2) (meaning we have more oxygen than we could ever use) -> 2CO2 + H2O + n(O2)

Therefore, to get the number of molecules of CO2 from this reaction, just double the molecules of acetylene and you're golden.

How acetylene ACTUALLY burns is a little different. Three reactions occur simultaneously:

C2H2 + O2 -> 2CO + H2

2CO + O -> 2CO2

2H2 + O2 -> 2H2O

It does this because acetylene is so energetic it can't wait to split two molecules of oxygen apart before it reacts.

But at the end of it, you still get two CO2 molecules for every acetylene molecule.

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Q: How many molecules of carbon dioxide are produced when 133 molecules of acetylene (HCCH) to react in excess oxygen produce carbon dioxide water?
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