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How many molecules of dinitrogen peroxide are in 2.88 moles of dinitrogen pentoxide?
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What is the empirical formula for the compound that is made of 1.85 moles of nitrogen and 4.63 moles of oxygen?
You think probable to dinitrogen pentoxide - N2O5.
What is the mass of 3.28 moles of dinitrogen tetroxide?
The mass of 3,28 moles of dinitrogen tetroxide is 301,8 g.
How many moles of oxygen atoms are present in 5.50 mol of diphosphorus pentoxide?
five
How many Na2SO4 molecules are present in 1.125 moles?
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
How many moles of water H2O contain 2.0X1022 molecules of water?
6,022140857.1023 molecules---------------------------------------------1 mole2.1022 molecules--------------------------------------------------------------x molex = 0,033 moles
What is the empirical formula for the compound that is made of 1.85 moles of nitrogen and 4.63 moles of oxygen?
You think probable to dinitrogen pentoxide - N2O5.
How much would two moles of dinitrogen pentoxide weigh?
The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g
How many moles of oxygen atoms are present in 5.00 moles of diphosphorous pentoxide?
Diphosphorus pentoxide has 5 oxygen atoms per molecule according to the given prefix. So, 5 moles of it will be 5 x 5 x (6.022x10^23) = 1.51x10^25 oxygen atoms.
What is the mass of 3.28 moles of dinitrogen tetroxide?
The mass of 3,28 moles of dinitrogen tetroxide is 301,8 g.
How many molecules of dinitrogen monoxide are present in 2.30 moles of this compound?
2.30 x 6.023 x 1023 = 13.85 x 1023
How many molecules of water make up 5 moles?
for each mole of anything there is 6.022x10^23 molecules. Therefore for 5 moles of water there is 5 x 6.022x10^23 = 3.011x10^24 molecules of water
How many molecules are in P2O5?
The formula P2O5, could itself represent one molecule of diphosphorus pentoxide. Or you could specify any number of moles. One mole of P2O5 would be 6.022 x 1023 molecules of P2O5. Two moles would be 1.204 x 1024 molecules, and so on.
How many molecules are present in 1296 g of dinitrogen pentoxide?
Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.
How many moles of oxygen atoms are present in 5.00mol of diphosphorus pentoxide P2O5?
There is 25.0 moles Oxygen
How many MOLES of dinitrogen tetraoxide are present in 4.00 grams of this compound?
Dinitrogen tetraoxide, or N2O4 has a molar mass of 92.011 grams per mole. This means there are 0.0435 moles present.
How many grams are there in a container of 2.26x1025 molecules of dinitrogen trisufide?
In order to answer this question you need to know the molar mass of dinitrogen trisulfide (N2S3), and that 1 mole of molecules is equal to 6.022 x 1023 molecules. Molar mass is determined by multiplying each element's subscript by that element's atomic weight on the periodic table, and expressing it in grams/mole.1 mole N2S3 molecules = 6.022 x 1023 molecules N2S3molar mass N2S3 = 124.208g/molConvert molecules to moles.2.26 x 1025 molecules N2S3 x (1mol N2S3/6.022 x 1023 molecules N2S3) = 37.5 moles N2S3Convert moles to mass in grams.37.5mol N2S3 x (124.208g N2S3/1mol N2S3) = *4660 grams N2S3*The answer is rounded to three significant figures.
How many moles of oxygen atoms are present in 5.50 mol of diphosphorus pentoxide?
five
