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How many molecules of dinitrogen peroxide are in 2.88 moles of dinitrogen pentoxide?
Since dinitrogen pentoxide has the chemical formula N2O5, it contains two nitrogen atoms. Therefore, for every molecule of N2O5, there are two molecules of N2O. In 2.88 moles of N2O5, there would be 2.88 x 2 = 5.76 moles of N2O. Finally, since 1 mole of N2O contains 2 molecules of N2, there would be 5.76 x 2 = 11.52 moles of N2 molecules.
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What is the empirical formula for the compound that is made of 1.85 moles of nitrogen and 4.63 moles of oxygen?
You think probable to dinitrogen pentoxide - N2O5.
What is the mass of 3.28 moles of dinitrogen tetroxide?
The mass of 3,28 moles of dinitrogen tetroxide is 301,8 g.
What is the mass of 3.97x1021 molecules dinitrogen tetraoxide?
To calculate the mass of 3.97x10^21 molecules of dinitrogen tetraoxide, you first need to find the molar mass of dinitrogen tetraoxide (N2O4), which is about 92.02 g/mol. Then you can use Avogadro's number (6.022x10^23 molecules/mol) to convert molecules to moles and then multiply by the molar mass to find the mass.
How many moles of oxygen atoms are present in 5.50 mol of diphosphorus pentoxide?
five
What is the balanced chemical reaction when dinitrogen pentoxide reacts with water?
First write the equation out without coefficients unless you're given them __N2(g)+__O2(g)-->__N2O5(g) Then balance the equation, making sure that the products equal the reactants. Your answer should have 4 moles of N and 10 moles of O on each side. 2N2(g)+5O2(g)-->2N2O5
How many molecules are present in 1296 g of dinitrogen pentoxide?
Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.
What is the empirical formula for the compound that is made of 1.85 moles of nitrogen and 4.63 moles of oxygen?
You think probable to dinitrogen pentoxide - N2O5.
How many molecules are present in 1296 g of dinitrogen pentoxide (N2O5)?
To find the number of molecules in 1296 g of dinitrogen pentoxide (N2O5), first calculate the molar mass of N2O5 which is 108 g/mol. Then, divide the given mass by the molar mass to get the number of moles (12 moles). Finally, use Avogadro's constant (6.022 x 10^23) to convert moles to molecules, giving approximately 7.2 x 10^23 molecules.
How much would two moles of dinitrogen pentoxide weigh?
The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g
How many molecules of dinitrogen monoxide are present in 2.30 moles of this compound?
There are (1.39 \times 10^{24}) molecules of dinitrogen monoxide in 2.30 moles of the compound, calculated by multiplying Avogadro's number (6.022 x 10^23 molecules/mole) by the number of moles provided.
What is the mass of 3.28 moles of dinitrogen tetroxide?
The mass of 3,28 moles of dinitrogen tetroxide is 301,8 g.
How many moles of oxygen atoms are present in 5.00 moles of diphosphorous pentoxide?
In diphosphorous pentoxide (P4O10), there are 10 oxygen atoms for every molecule. Therefore, in 5.00 moles of diphosphorous pentoxide, there would be 5.00 moles x 10 oxygen atoms = 50.0 moles of oxygen atoms.
What is the mass of 3.97x1021 molecules dinitrogen tetraoxide?
To calculate the mass of 3.97x10^21 molecules of dinitrogen tetraoxide, you first need to find the molar mass of dinitrogen tetraoxide (N2O4), which is about 92.02 g/mol. Then you can use Avogadro's number (6.022x10^23 molecules/mol) to convert molecules to moles and then multiply by the molar mass to find the mass.
What volume of dinitrogen pentoxide gas is produced when 500 ml of oxygen react completely in the following equation of STP 2N2 and 5O2 equals 2N2O5?
Using the stoichiometry of the balanced chemical equation, we find that 5 moles of oxygen gas will produce 2 moles of dinitrogen pentoxide gas. At STP (standard temperature and pressure, 0 degrees Celsius and 1 atm pressure), 1 mole of ideal gas occupies 22.4 L. So, first calculate the number of moles of oxygen gas from the given volume of 500 ml using the ideal gas law. Then, use the stoichiometry of the balanced chemical equation to determine the volume of dinitrogen pentoxide gas produced (in liters) at STP.
How many molecules are there in 29.777 grams of hydrogen peroxide H2O2?
To find the number of molecules in 29.777 grams of hydrogen peroxide (H2O2), you first need to calculate the number of moles in 29.777 grams using the molar mass of H2O2. Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
How many MOLES of dinitrogen tetraoxide are present in 4.00 grams of this compound?
Dinitrogen tetraoxide, or N2O4 has a molar mass of 92.011 grams per mole. This means there are 0.0435 moles present.
How many grams are there in a container of 2.26x1025 molecules of dinitrogen trisufide?
In order to answer this question you need to know the molar mass of dinitrogen trisulfide (N2S3), and that 1 mole of molecules is equal to 6.022 x 1023 molecules. Molar mass is determined by multiplying each element's subscript by that element's atomic weight on the periodic table, and expressing it in grams/mole.1 mole N2S3 molecules = 6.022 x 1023 molecules N2S3molar mass N2S3 = 124.208g/molConvert molecules to moles.2.26 x 1025 molecules N2S3 x (1mol N2S3/6.022 x 1023 molecules N2S3) = 37.5 moles N2S3Convert moles to mass in grams.37.5mol N2S3 x (124.208g N2S3/1mol N2S3) = *4660 grams N2S3*The answer is rounded to three significant figures.
