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The gram molecular mass of C2H4 is 28.05. Therefore, 1.26 X 103 grams constitutes (1.26/28.05) X 103 or about 44.9 moles. Each mole contains Avogadro's number of molecules; therefore, 1.26 X 103 grams contains 2.71 X 1025 molecules, to the justified number of significant digits.

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Q: How many molecules of in 1.26 x 10 3 grams of c2h4?
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