Only one mole
* Assuming it's liquid * Molecular weight : 28.0134 g/mol * Liquid density (1.013 bar at boiling point) : 808.607 kg/m3=808.607g/L 10.5L = 8490.3735 g divide by 28.0134 = 303.0825 mol
0,125 L neon is equivalent to 0,0056 moles.
300 moles of nitrogen equals 8404,2 g.The density of nitrogen at 20 oc and 1 at is 1,251 g/cm3.8404,2 g nitrogen equals 6 718 L.1 kL = 1 000 LSo the volume of 300 moles N2 is 6,718 kL.
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
4 g of Helium = 1 mole.So, 56 g of helium = 14 moles
The volume is 4908 L at oC.
To find the mass of N2, first calculate the moles of N2 using the ideal gas law: PV = nRT. Then use the molar mass of N2 to convert moles to grams. Given that the volume is 3.0 L, the temperature is 100°C (373 K), and the pressure is 700 mmHg (93.3 kPa), you can substitute these values into the ideal gas law to find the moles of N2.
* Assuming it's liquid * Molecular weight : 28.0134 g/mol * Liquid density (1.013 bar at boiling point) : 808.607 kg/m3=808.607g/L 10.5L = 8490.3735 g divide by 28.0134 = 303.0825 mol
95,474 moles
To find the moles of N2, we need to use the ideal gas law equation: PV = nRT. First, convert 400.0 mL to liters (0.400 L). Then convert 780 mmHg to atm (0.998 atm), and 135 degrees Celsius to Kelvin (408 K). Plug these values into the equation to solve for n, which gives you the moles of N2 in the container.
To find the number of moles of N2 in the flask, we can first calculate the number of molecules using the ideal gas law equation PV = nRT. Then, convert the number of molecules to moles by dividing by Avogadro's number, which is 6.022 x 10^23 mol^-1. Calculate the number of moles using: n = PV / RT. Given P= 300.0 kPa, V= 0.25 L, T= 300.0 K, R= 8.31 LkPa/(Kmol), the number of moles of N2 can be calculated.
4,54 L of CO have 0,182 moles.
0,125 L neon is equivalent to 0,0056 moles.
300 moles of nitrogen equals 8404,2 g.The density of nitrogen at 20 oc and 1 at is 1,251 g/cm3.8404,2 g nitrogen equals 6 718 L.1 kL = 1 000 LSo the volume of 300 moles N2 is 6,718 kL.
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
Molarity is moles of solute per L of solution.moles KCl = ( 1.68 M ) ( 0.121 L ) = ( 1.68 mol/L ) ( 0.121 L )moles KCl = 0.203 moles KCl
4 g of Helium = 1 mole.So, 56 g of helium = 14 moles