answersLogoWhite

0

* Assuming it's liquid * Molecular weight : 28.0134 g/mol * Liquid density (1.013 bar at boiling point) : 808.607 kg/m3=808.607g/L 10.5L = 8490.3735 g divide by 28.0134 = 303.0825 mol

User Avatar

Wiki User

16y ago

What else can I help you with?

Related Questions

How many moles of N2 are in a flask with a volume of 250ml at a pressure of 300.0 kPa and a temperature of 300.0 K?

To find the number of moles of N2 in the flask, we can first calculate the number of molecules using the ideal gas law equation PV = nRT. Then, convert the number of molecules to moles by dividing by Avogadro's number, which is 6.022 x 10^23 mol^-1. Calculate the number of moles using: n = PV / RT. Given P= 300.0 kPa, V= 0.25 L, T= 300.0 K, R= 8.31 LkPa/(Kmol), the number of moles of N2 can be calculated.


How many moles of N2 are in 50g of it?

To determine the number of moles of N2 in 50g, you first need to find the molar mass of N2 (28.02 g/mol). Then, you divide the given mass (50g) by the molar mass to get the number of moles. In this case, 50g / 28.02 g/mol ≈ 1.79 moles of N2.


How many molecules of Nitrogen are in 3.5 grams of N2?

To find the number of molecules of N2 in 3.5 grams, first calculate the number of moles using the molar mass of N2 (28 g/mol). Then use Avogadro's number (6.022 x 10^23 molecules/mol) to convert the moles to molecules.


How many moles of N2 are produced by the decomposition of 1.20 mol of NaN3?

The number of atoms is 45,166.10e23.


How do you find the number of moles of nitrogen gas in 3.2L?

1 mole N2 = 22.4L 3.2L N2 x 1mol N2/22.4L = 0.14 mole N2


Find the mass in grams of 4.00x1023 molecules of N2?

1 mole N2 = 28.0134g 1 mole N2 = 6.022 x 1023 molecules N2 28.0134g N2 = 6.022 x 1023 molecules N2 (4.00 x 1023 molecules N2) x (28.0134g/6.022 x 1023 molecules) = 18.6g N2


How many grams of nitrogen are required to react with 2.79 g of hydrogen to produce ammonia?

In the reaction 3H2 + N2 --> 2NH3, the ratio of H2 to N2 is 3:1. To calculate the amount of N2 required, we need to first convert the mass of H2 to moles, then use the ratio to find the moles of N2 needed, and finally convert the moles of N2 to grams. After the calculation, we find that 2.79 g of H2 requires 3.31 g of N2 to react completely.


How do you get the number of moles in 28grams per mole of N2?

Use the dimensional analysis to get your answer


How many moles of NH3 can be produced from 14 grams of N2?

The molecular mass of NH3 is the sum of the atomic mass of nitrogen and three times the atomic mass of hydrogen, or 14.007 + 3(1.008) = 17.031. Therefore, the number of moles of NH3 in 14.0 grams is 14.007/17.031 = 0.822. Since each molecule of N2 supplies two nitrogen atoms and each molecule of NH3 needs only one nitrogen atom, the number of moles of N2 needed is half the number of moles of NH3 formed = 0.411.


If 5.0 moles of NH3 are produce how many moles of N2 must have been used?

If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.


What mass of NH3 is produced when 1.20 mol of N2 react completely in the following equation N2 plus 3H2 2NH3?

N2 + 3H2 ==> 2NH3moles N2 = 1.20 molesmoles NH3 formed = 1.20 moles N2 x 2 moles NH3/1 moles N2 = 2.40 moles NH3mass NH3 = 2.40 moles x 17 g/mole = 40.8 g NH3


How many moles of H2are needed to react with 0.90moles N2?

Assuming a balanced chemical equation, you would need 3 moles of H2 to react with 1 mole of N2. Therefore, if you have 0.90 moles of N2, you would need 0.90 x 3 = 2.70 moles of H2 to fully react with it.