* Assuming it's liquid * Molecular weight : 28.0134 g/mol * Liquid density (1.013 bar at boiling point) : 808.607 kg/m3=808.607g/L 10.5L = 8490.3735 g divide by 28.0134 = 303.0825 mol
To determine the number of moles of N2 in 50g, you first need to find the molar mass of N2 (28.02 g/mol). Then, you divide the given mass (50g) by the molar mass to get the number of moles. In this case, 50g / 28.02 g/mol ≈ 1.79 moles of N2.
The number of atoms is 45,166.10e23.
1 mole N2 = 28.0134g 1 mole N2 = 6.022 x 1023 molecules N2 28.0134g N2 = 6.022 x 1023 molecules N2 (4.00 x 1023 molecules N2) x (28.0134g/6.022 x 1023 molecules) = 18.6g N2
Use the dimensional analysis to get your answer
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
To find the number of moles of N2 in the flask, we can first calculate the number of molecules using the ideal gas law equation PV = nRT. Then, convert the number of molecules to moles by dividing by Avogadro's number, which is 6.022 x 10^23 mol^-1. Calculate the number of moles using: n = PV / RT. Given P= 300.0 kPa, V= 0.25 L, T= 300.0 K, R= 8.31 LkPa/(Kmol), the number of moles of N2 can be calculated.
To determine the number of moles of N2 in 50g, you first need to find the molar mass of N2 (28.02 g/mol). Then, you divide the given mass (50g) by the molar mass to get the number of moles. In this case, 50g / 28.02 g/mol ≈ 1.79 moles of N2.
To find the number of molecules of N2 in 3.5 grams, first calculate the number of moles using the molar mass of N2 (28 g/mol). Then use Avogadro's number (6.022 x 10^23 molecules/mol) to convert the moles to molecules.
The number of atoms is 45,166.10e23.
1 mole N2 = 22.4L 3.2L N2 x 1mol N2/22.4L = 0.14 mole N2
1 mole N2 = 28.0134g 1 mole N2 = 6.022 x 1023 molecules N2 28.0134g N2 = 6.022 x 1023 molecules N2 (4.00 x 1023 molecules N2) x (28.0134g/6.022 x 1023 molecules) = 18.6g N2
In the reaction 3H2 + N2 --> 2NH3, the ratio of H2 to N2 is 3:1. To calculate the amount of N2 required, we need to first convert the mass of H2 to moles, then use the ratio to find the moles of N2 needed, and finally convert the moles of N2 to grams. After the calculation, we find that 2.79 g of H2 requires 3.31 g of N2 to react completely.
Use the dimensional analysis to get your answer
The molecular mass of NH3 is the sum of the atomic mass of nitrogen and three times the atomic mass of hydrogen, or 14.007 + 3(1.008) = 17.031. Therefore, the number of moles of NH3 in 14.0 grams is 14.007/17.031 = 0.822. Since each molecule of N2 supplies two nitrogen atoms and each molecule of NH3 needs only one nitrogen atom, the number of moles of N2 needed is half the number of moles of NH3 formed = 0.411.
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
N2 + 3H2 ==> 2NH3moles N2 = 1.20 molesmoles NH3 formed = 1.20 moles N2 x 2 moles NH3/1 moles N2 = 2.40 moles NH3mass NH3 = 2.40 moles x 17 g/mole = 40.8 g NH3
Assuming a balanced chemical equation, you would need 3 moles of H2 to react with 1 mole of N2. Therefore, if you have 0.90 moles of N2, you would need 0.90 x 3 = 2.70 moles of H2 to fully react with it.