1 mole equals 6.022 x 10 to the 23 molecules
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
You take Avogadro's number and multiply it because that multiplies it by the amount of atoms/molecules in one mole.
98,3 molecules of aluminum hydroxide Al(OH)3 is equivalent to 16,323.10e-23 moles.
To get moles given representative particles, simply divide by Avogadro's number: 1.80x1024/6.02x1023 = approx. 3 moles I2.
1 mole is 6.022 141 293 x 1023 molecules. (Avogadro's constant). If you have 3 moles of CO2, then you have 3 x 6.022 141 293 x 1023 molecules = 1.806642388 x 1024 molecules!
The number of ammonia molecules is 5,83.10e19.
The value is 1,328.10e-3 moles.
98,3 molecules of aluminum hydroxide Al(OH)3 is equivalent to 16,323.10e-23 moles.
To get moles given representative particles, simply divide by Avogadro's number: 1.80x1024/6.02x1023 = approx. 3 moles I2.
3
1 mole is 6.022 141 293 x 1023 molecules. (Avogadro's constant). If you have 3 moles of CO2, then you have 3 x 6.022 141 293 x 1023 molecules = 1.806642388 x 1024 molecules!
3 x 12 = 36 moles of Nitrogen atoms N or 18 moles of Nitrogen molecules N2
3 moles of Ca would have 1.806 × 10^24 atoms.
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
8.5x10^-3 moles x 6.02x10^23 molecules/mole = 5.1x10^-19 molecules
The number of ammonia molecules is 5,83.10e19.
The value is 1,328.10e-3 moles.
It does NOT form molecules. When AlCl3 'breakdown ' it form the IONS Al^(3+) & 3 Cl^(-) AlCl3(s) IS a molecule.