20 g NaOH is equivalent to 20(g) /[23+16+1](g/mol) = 0.5 mol NaOH
This will react with 0.5 mol H+ which is present in 0.25 mol H2SO4
For this you'll need 0.25(mol) /2.0(mol/L) = 0.125 L = 125 mL of 2.0 M H2SO4-solution.
80 g sulfuric acid is equivalent to 0,816 moles.
The correct answer is 17,65 g or 0,18 moles.
1 mole.
The formula weight of sulfuric acid is 98.1 grams per mole. Dividing 100 grams by the formula weight gets you 1.01 moles.
The answer is o,2 mol.
The answer is 0,05 mol and 4,9 g.
1.96g
0.1
5 moles
0.010 moles The molar mass of H2SO4 is 98.1 grams per mole. To find out how many moles are present in a given mass, divide the mass by the molar mass. So: 1g/98.1g mol-1 is 0.010 mol.
There are 1.5 moles water in 27 grams
196 grams H2SO4 (1 mole H2SO4/98.096 grams)(6.022 X 10^23/1 mole H2SO4) = 1.20 X 10^24 molecules of sulfuric acid
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
5 moles
0.010 moles The molar mass of H2SO4 is 98.1 grams per mole. To find out how many moles are present in a given mass, divide the mass by the molar mass. So: 1g/98.1g mol-1 is 0.010 mol.
There are 1.5 moles water in 27 grams
the mole is 30 g.
196 grams H2SO4 (1 mole H2SO4/98.096 grams)(6.022 X 10^23/1 mole H2SO4) = 1.20 X 10^24 molecules of sulfuric acid
The answer is 6,31 moles Ag.
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
No. of moles=given mass/gram molecular mass =16/16 =1
80,0 moles of CO2is equal to 3 520,8 g.
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
Sulfuric acid is not obtained from water.
.565 MOLES