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20 g NaOH is equivalent to 20(g) /[23+16+1](g/mol) = 0.5 mol NaOH

This will react with 0.5 mol H+ which is present in 0.25 mol H2SO4

For this you'll need 0.25(mol) /2.0(mol/L) = 0.125 L = 125 mL of 2.0 M H2SO4-solution.

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9y ago
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8y ago

80 g sulfuric acid is equivalent to 0,816 moles.

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Nizalia Amir

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1y ago
How many moles in 80g of h2so4
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Damini Gondane

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1y ago
0.816

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11y ago

The correct answer is 17,65 g or 0,18 moles.

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11y ago

1 mole.

The formula weight of sulfuric acid is 98.1 grams per mole. Dividing 100 grams by the formula weight gets you 1.01 moles.

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11y ago

The answer is o,2 mol.

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11y ago

The answer is 0,05 mol and 4,9 g.

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11y ago

1.96g

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10y ago

0.1

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Q: How many moles are present in a sample of H2SO4 with a mass of 9.8g?
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