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196 grams H2SO4 (1 mole H2SO4/98.096 grams)(6.022 X 10^23/1 mole H2SO4)
= 1.20 X 10^24 molecules of sulfuric acid
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∙ 13y ago
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How many moles of sulfur are present in 5 moles of H2So4?
5 moles
How many moles are present in 1g of H2So4?
0.010 moles The molar mass of H2SO4 is 98.1 grams per mole. To find out how many moles are present in a given mass, divide the mass by the molar mass. So: 1g/98.1g mol-1 is 0.010 mol.
How many moles of sulfuric acid are in 500 mL of 0.324 M sulfuric acid solution?
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
How many moles of H are in 0.75 moles of H2SO4?
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
How many moles are in 3.4 times 10 to the 23 power molecules of H2SO4?
.565 MOLES
How many moles of sulfur are present in 5 moles of H2So4?
5 moles
How many moles are present in 1g of H2So4?
0.010 moles The molar mass of H2SO4 is 98.1 grams per mole. To find out how many moles are present in a given mass, divide the mass by the molar mass. So: 1g/98.1g mol-1 is 0.010 mol.
How many moles of sulfuric acid are in 500 mL of 0.324 M sulfuric acid solution?
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
How many moles of H are in 0.75 moles of H2SO4?
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
How many moles are in 3.4 times 10 to the 23 power molecules of H2SO4?
.565 MOLES
How many moles of H2SO4 are produced from 13 moles of H2O?
Sulfuric acid is not obtained from water.
How many H2SO4 molecules are there in 9.62 moles of H2SO4?
9.62 Mol H2SO4 ( 6.022 X 10^23/1mol H2SO4 ) = 5.79 X 10^24 molecules of H2SO4
How many moles of which reactant are in excess when 359.0 mL of 0.259 M sulfuric acid reacts with 0.510 L of 0.191 M sodium hydroxide to form water and aqueous sodium sulfate?
Balanced equation first. 2NaOH + H2SO4 -> Na2SO4 +2H2O Molarity = moles of solute/Liters of solution 0.259 M H2SO4 = moles H2SO4/0.359 liters = 0.09298 moles H2SO4 0.191 M NaOH = moles of NaOH/0.510 liters = 0.09741 moles NaOH ( Let us find limiting reactant ) 0.09298 moles H2SO4 (1 mole H2SO4/2 mole NaOH) = 0.04649 moles H2SO4-- Sulfuric acid limits and, 0.04648 moles of sodium hydroxide are in excess.
How many atoms of oxygen in 335 mole of H2SO4?
Quite a few! 335 moles H2SO4 (4 moles O/1 mole H2SO4)(6.022 X 1023/1 mole O) = 8.07 X 1026 atoms of oxygen =======================
How many molecusles are contained in 55.0 g of H2SO4?
how many molecules are containd in 55.0g of H2SO4
How many moles Mg react with 0.20 moles H2SO4?
If you want all the H2SO4 to react, you first need a balenced chemical equasion. Mg + H2SO4 --> MgSO4 +H2 Then you calculate using mole ratios moles is expressed as n. n Mg/1 =n H2SO4/1 n Mg= 0.2mol It's the same because there are no coefficients in front of the reactants.
How many hydrogen atoms are in 0.09 moles of H2SO4 Please explain as well?
Just moles against the ratio of hydrogen atoms in compound then against Avogadro's number. Like this 0.09 moles H2SO4 (2 moles H/1 mole H2SO4)(6.022 X 10^23/1 mole H) = 1.1 X 10^23 hydrogen atoms
