22.4g/98.09 g/mol = 0.228mol
Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
573,28 of g of AgCI is equivalent to 4 moles.
To determine the number of moles in 1g of H2SO4, you first need to calculate the molar mass of H2SO4. The molar mass of H2SO4 is approximately 98.08 g/mol. Therefore, 1g of H2SO4 is equal to 0.0102 moles (1g / 98.08 g/mol).
To find the number of moles in 98.1 g of H2SO4, first calculate the molar mass of H2SO4 (98.1 g/mol). Then, divide the given mass by the molar mass to find the number of moles (98.1 g / 98.1 g/mol = 1 mol). Therefore, there is 1 mole in 98.1 g of H2SO4.
how many molecules are containd in 55.0g of H2SO4
To calculate the mass of a substance in grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of H2SO4 (sulfuric acid) is approximately 98.08 g/mol. Therefore, the mass of 6.25 moles of H2SO4 would be 6.25 moles x 98.08 g/mol = 613 grams.
Did you mean 0.5 g? or mg? or ml?Anyway, amount of substance in moles is calculated as m/Mwhere m is mass and M is molal mass.M (H2SO4) is 1*2 + 32 + 16*4 = 98 g/mole
To find the mass of 3.60 moles of H2SO4, you first need to calculate the molar mass of H2SO4. The molar mass of H2SO4 is 98.08 g/mol. Multiply the molar mass by the number of moles to get the mass: 3.60 moles * 98.08 g/mol = 353.088 grams. Therefore, the mass of 3.60 moles of H2SO4 is 353.088 grams.
We need to go from grams of CuO to mL of H2SO4. Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO (.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel) Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4 3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4 (0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel) So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.
To convert moles to grams, you need to use the molar mass of the compound. The molar mass of H2SO4 is 98.08 g/mol. Therefore, 0.736 moles of H2SO4 is equal to 0.736 * 98.08 = 72.16 grams.
To calculate the mass of H2SO4, you first find the moles of H2SO4 using the molarity formula (moles = molarity x volume). Then use the molar mass of H2SO4 (98.08 g/mol) to convert moles to grams. Given that the solution is 5.85 M, you would first calculate moles of H2SO4: 5.85 mol/L x 0.060 L = 0.351 mol. Then convert moles to grams: 0.351 mol x 98.08 g/mol ≈ 34.44 grams of H2SO4.
To calculate the mass of H2SO4 required, first calculate the number of moles needed using the formula: moles = molarity x volume (in liters). Then, multiply the moles by the molar mass of H2SO4 (98.08 g/mol) to find the mass. moles = 0.15 mol/L x 0.75 L = 0.1125 mol mass = 0.1125 mol x 98.08 g/mol ≈ 11.04 g of H2SO4.
196 grams H2SO4 (1 mole H2SO4/98.096 grams)(6.022 X 10^23/1 mole H2SO4) = 1.20 X 10^24 molecules of sulfuric acid
The weight of 2,5 mol of sulfuric acid is 245,1975 g.