The formula mass of sodium hydroxide, NaOH is 23.0+16.0+1.0=40.0
Amount of NaOH in 25.0g sample = 0.625mol
25 grams NaCl * 1 mole NaCl per = .43 moles NaCl
58.44 grams NaCl (molecular mass)
25.0 grams NaOH (1 mole NaOH/39.998 grams)(6.022 X 10^23/1 mole NaOH)(1 mole NaOH atoms/6.022 X 10^23)
= 0.625 moles of sodium hydroxide atoms
25g/1 * 1 mol/40.01g =0.63 mol NaOH
Since NaOH is a strong base, one mole (6.022x1023) of Na+ ions are formed when one mole of NaOH dissolves in water.
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
1 mole NaOH = 39.99664g (from the atomic weights on the periodic table) 15g NaOH x 1mol/39.99664g = 0.38 mole NaOH
There is one hydrogen atom in one formula unit of NaOH.
This is acetic acid which is monobasic acid so one mole of it is neutralized by one mole of NaOH.
Since NaOH is a strong base, one mole (6.022x1023) of Na+ ions are formed when one mole of NaOH dissolves in water.
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
1 mole NaOH = 39.99664g (from the atomic weights on the periodic table) 15g NaOH x 1mol/39.99664g = 0.38 mole NaOH
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
There is one hydrogen atom in one formula unit of NaOH.
No, they are not. "0.5 mole of NaOH" means that you have half a mole of sodium hydroxide. "0.5M of NaOH" means that you have half a mole of sodium hydroxide for every liter of solution. "0.5M" is also commonly written as "0.5 mol/L" or "mol L-1".
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
sodium hydroxide is NaOH so its atomic mass is 23+1+16=40 so one mole of NaOH contains 40 grams and 6.023*10^23 molecules hence 10 grams will have 0.25 moles and hence 0.25*6.023*10^23 molecules ==1.0575 *10^23 molcules now 1 molecule of NaOH has 3 atoms so total no of atoms in 10 gram is 1.0575*3*10^23=1.592330625810^23 atoms