At standard temperature and pressure (STP), one mole of a gas is 22.4L.
So, in order to determine how many moles of O2 are in 30L, you do the following:
multiply 30L O2 x 1mol O2/22.4L O2, which equals 1.34mol O2.
Depends what temperature & pressure of the gas is.
PV = nRT
(1atm)(300 L) = n(moles)(0.08206 L*atm/mol*K)(298.15 K)
= 12.3 moles of CO2
44.8 liters in 2 moles of CO2
using the equation moles=mass/molar mass (since its in gas form) O2 => 16*2 =32 0.16/32=0.005 moles :)
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
.913 moles
I was wondering about this... but I think if you combined..The four oxygen gas O2, and the two of Hydrogen gas H2.. and predict was will happened I guess this is what it will or might be calculate, but Im not sure.KKKO2O2+H2H1O4+H2O2H
The answer is 0,173 moles.
The answer is 0,8 moles oxygen.
6,5 moles oxygen equals 208 g.
The equivalent in moles is 6,03.
The answer is 2 moles.
The mass of 0,2 moles of oxygen gas is 6,4 g.
1 mole.
3.058
30 moles
using the equation moles=mass/molar mass (since its in gas form) O2 => 16*2 =32 0.16/32=0.005 moles :)
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
We need 3 moles of potassium perchlorate.