The mass of 0,2 moles of oxygen gas is 6,4 g.
The answer is 1,72 moles.
oxygen
15 moles of 02 equal 480 g.
01. natural gas 02. oxygen 03.carbondioxide 04. nitrogen
there are many combustion equations. the equation will look like this: x moles of "the gas" are combusted with x moles of oxygen gas to yield x moles of dihydrogen monoxide and x moles of carbon dioxide.example: two moles of butane(C2H6) combust with four moles of oxygen gas(02) yield two moles of dihydroggen monoxide(water: h20) and two moles of carbon dioxide(CO2)hmm well i don't really think that answers the question very well so whoever wrote this may need to add some thing to it or reword it for it to be easier to understand.Try this instead.......Combustion of a fuel (such as methane)Lots of oxygen presentMethane + oxygen -----------> Carbon dioxide + waterSome oxygen presentMethane + oxygen -----------> Carbon monoxide + waterLittle oxygen presentMethane + oxygen ------------> Carbon (soot) + waterI also agree that the first paragraph is a little vague and I would just like to say that the term Dihydrogen Monoxide was a hoax and is not the actual term for water. If you want to use the IUPAC name you can: OxidaneIUPAC: International Union of pure and applied chemistry
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
The answer is 1,72 moles.
oxygen
Since there are two oxygen molecules, the molar mass would be twice the atomic weight given in the periodic table of elements. O = 16 g/mole O2 = 32 g/mole
Since we know that one mole of any gas at STP is equal to 22.4 L we can multiply 135L by the following conversion: 1 mole/22.4L. When you set up the problem it looks like this: (135L)x 1 mole/22.4L =6.03 moles of oxygen gas The liters cancel out and you are left with moles as your units. Remember, if you have liters and want moles, divide by 22.4 liters; if you have moles and you want liters you multiply by 22.4 liters.
1 mole of 02 gas has 12,044 281 714.1023 atoms.
It's Oxygen but in gas form. Such as N2 is nitrogen gas. But just N is nitrogen.
15 moles of 02 equal 480 g.
01. natural gas 02. oxygen 03.carbondioxide 04. nitrogen
The element O2 (oxygen gas) is made up of two oxygen atoms bonded together.
See the Related Question linked the the left of this answer: = How do you solve an Ideal Gas Law problem? = Note that STP is standard temperature and pressure. Standard pressure is 1 atm, and standard temperature is 0 °C, which is 273.15 Kelvin.
there are many combustion equations. the equation will look like this: x moles of "the gas" are combusted with x moles of oxygen gas to yield x moles of dihydrogen monoxide and x moles of carbon dioxide.example: two moles of butane(C2H6) combust with four moles of oxygen gas(02) yield two moles of dihydroggen monoxide(water: h20) and two moles of carbon dioxide(CO2)hmm well i don't really think that answers the question very well so whoever wrote this may need to add some thing to it or reword it for it to be easier to understand.Try this instead.......Combustion of a fuel (such as methane)Lots of oxygen presentMethane + oxygen -----------> Carbon dioxide + waterSome oxygen presentMethane + oxygen -----------> Carbon monoxide + waterLittle oxygen presentMethane + oxygen ------------> Carbon (soot) + waterI also agree that the first paragraph is a little vague and I would just like to say that the term Dihydrogen Monoxide was a hoax and is not the actual term for water. If you want to use the IUPAC name you can: OxidaneIUPAC: International Union of pure and applied chemistry