1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
456
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
3.20 moles aluminum (6.022 X 1023/1 mole Al) = 1.93 X 1024 atoms of aluminum -------------------------------------------
27g
1,99 grams of aluminum is equal to 0,0737 moles.
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------
The Answer is.56 moles OR 0.56 moles
4 moles
4 moles
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
456
1,075 moles of aluminium chloride are obtained.
9
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
3.20 moles aluminum (6.022 X 1023/1 mole Al) = 1.93 X 1024 atoms of aluminum -------------------------------------------